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Colt1911 [192]
3 years ago
13

Plzzzzzzzzzzz help what is a font!

Chemistry
1 answer:
spayn [35]3 years ago
6 0

Answer:

1. a receptacle in a church for the water used in baptism, typically a freestanding stone structure.

2. A type of writing or text style

Explanation:

There are mutiple definitions of font

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Another carbon isotope has six protons and seven neutrons in its nucleus. What do you think this carbon isotope is called?
insens350 [35]

Answer:

Carbon - 13

Explanation:

For most of the elements other than that of hydrogen, the isotopes are named for the mass number.

Example : Carbon atoms with 6 neutrons have mass number of 12 ( as 6\ protons +6\ neutrons=12 ), so they are known as carbon-12.

Given that:

Protons = 6

Neutrons = 7

Mass = 6 + 7 = 13

So the name is Carbon - 13 . The symbol is ^{13}_{6}C

8 0
2 years ago
Read 2 more answers
How many electrons would be found in an isotope of silicon 29
kenny6666 [7]
14 electrons15 neutrons
5 0
3 years ago
Consider the following reaction: 2{\rm{ N}}_2 {\rm{O(}}g)\; \rightarrow \;2{\rm{ N}}_2 (g)\; + \;{\rm{O}}_2 (g)
fredd [130]

Answer:

a. 5.9 × 10⁻³ M/s

b. 0.012 M/s

Explanation:

Let's consider the following reaction.

2 N₂O(g) → 2 N₂(g) + O₂(g)

a.

Time (t): 12.0 s

Δn(O₂): 1.7 × 10⁻² mol

Volume (V): 0.240 L

We can find the average rate of the reaction over this time interval using the following expression.

r = Δn(O₂) / V × t

r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s

r = 5.9 × 10⁻³ M/s

b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:

5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s

4 0
3 years ago
Please help me it’s my birthday
GalinKa [24]

Answer:

ur answer would be D.)

Explanation:

Hope this helps

also happy birthday

5 0
3 years ago
When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction:
slamgirl [31]

Answer:

1.5 mole

Explanation:

Step 1:

The balanced equation for the reaction. This is illustrated below:

2Al(s) + 3Cl2(g) --> 2AlCl3(s)

Step 2:

Determination of the masses of Al and Cl2 that reacted from the balanced equation. This is illustrated below:

Molar Mass of Al = 27g/mol

Mass of Al from the balanced equation = 2 x 27 = 54g

Molar Mass of Cl2 = 2 x 35.5 = 71g/mol

Mass of Cl2 from the balanced equation = 3 x 71 = 213g

From the balanced equation,

54g of Al reacted.

213g of Cl2 reacted

Step 3:

Determination of the limiting reactant.

This is illustrated below:

From the balanced equation above,

54g of Al reacted with 213g of Cl2.

Therefore, 40.5g of Al will react with = (40.5 x 213)/54 = 159.75g of Cl2.

From the calculations made above, there are leftover of Cl2 as 159.75g reacted out of 212.7g. Therefore, Cl2 is the excess reactant and Al is the limiting reactant.

Step 4:

Determination of the number of mole in 40.5g of Al. This is illustrated below:

Molar Mass of Al = 27g/mol

Mass of Al = 40.5g

Number of mole of Al =?

Number of mole = Mass/Molar Mass

Number of mole of Al = 40.5/27

Number of mole of Al = 1.5 mole

Step 5:

Determination of the number of mole of AlCl3 produced When 40.5 g of Al and 212.7 g of Cl2 combine together. This is illustrated below:

2Al(s) + 3Cl2(g) --> 2AlCl3(s)

From the balanced equation above,

2 moles of Al produced 2 moles of AlCl3.

Therefore, 1.5 mole of Al will also produce 1.5 mole of AlCl3.

From the calculations made above, 1.5 mole of AlCl3 is produced When 40.5 g of Al and 212.7 g of Cl2 combine together.

8 0
3 years ago
Read 2 more answers
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