Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
Explanation:
Given:
= 237 K,
= 101.33 kPa,
= ?
= 300 K,
= 151.99 kPa,
= 0.50 L
Formula used is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
<u>Answer:</u> The concentration of sulfate ions in the solution is 0.0522 M
<u>Explanation:</u>
To calculate the the molarity of solution:, we use the equation:

Given mass of alum = 2.17 g
Molar mass of alum = 478.39 g/mol
Volume of solution = 175 mL
Putting values in above equation, we get:

The chemical equation for the ionization of alum follows:

1 mole of alum produces 1 mole of potassium ions, 1 mole of aluminium ions, 2 moles of sulfate ions and 12 moles of water
So, concentration of sulfate ions = 
Hence, the concentration of sulfate ions in the solution is 0.0522 M
Answer:
i hate chemistry w all my heart so i suggest maybe finding the worksheet on the internet or smthing :)
Explanation: