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3 years ago

Help would be much appreciated! i'll mark brainliest

Chemistry

1 answer:

GrogVix [38]3 years ago

8 0

Answer:

GROUP 2

Explanation:

u asked this already

i just dont understand...

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Is usually categorized to a specific area in the state known as a soil series

Vikentia [17]

Answer:

Soil series as established by the National Cooperative Soil Survey of the United States Department of Agriculture (USDA) Natural Resources Conservation Service are a level of classification in the USDA Soil Taxonomy classification system hierarchy. The actual object of classification is the so-called soil individual, or pedon.[1] Soil series consist of pedons that are grouped together because of their similar pedogenesis, soil chemistry, and physical properties. More specifically, each series consists of pedons having soil horizons that are similar in soil color, soil texture, soil structure, soil pH, consistence, mineral and chemical composition, and arrangement in the soil profile.[2] These result in soils which perform similarly for land use purposes.

Explanation:

hope its correct

6 0

3 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

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3 years ago

Which statement best describes the collisions of gas particles according to the kinetic-molecular theory?

erastovalidia [21]

<span>The statement best describes the collisions of gas particles according to the kinetic-molecular theory is that the collisions of gas particles in an ideal gas are completely elastic. An expansion in the quantity of gas particles in the holder expands the recurrence of impacts with the dividers and in this manner the weight of the gas. The last propose of the motor sub-atomic hypothesis expresses that the normal active vitality of a gas molecule depends just on the temperature of the gas.</span>

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3 years ago

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Vlad1618 [11]

Answer:

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Explanation:

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3 years ago

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When Na and Cl combine to form a compound, which atom(s) will become a cation?