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Ksenya-84 [330]
3 years ago
13

What name is given to bonds that involve the sharing of electrons? What name is given to bonds that involve the sharing of elect

rons? ionic covalent polar hydrogen
Chemistry
1 answer:
Alina [70]3 years ago
3 0

Answer:

Covalent bonds.

Explanation:

Covalent bonds are intermolecular bonds which involve the sharing of electrons between atoms or molecules and ions with close or near electronegativity values.

This usually form molecules. This is also the sharing of electrons donated by one of the atoms or by both of the atoms to form a molecule and at the same time obtain a stable octet state.

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How many bananas are equal to 7.50 moles of bananas?​
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Answer:

4.52×10^24

Explanation:

N = n × Na

where; N = no. of bananas

n = no. of moles

Na = Avogadro's constant

Which is 6.02×10^23

N = 7.5 × 6.02×10^23

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3 years ago
Which factor does not influence stream velocity
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The factor that does not influence stream velocity is DISCHARGE.
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Single and double replacement reactions practice WS CuCl2 +<br> F2 »<br> CuF2<br> +<br> Cl2
Lapatulllka [165]
CuCl2+F2—>CuF2+Cl2.
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7 0
3 years ago
N2H4 + N2O4 --&gt; N2 + H2O
ahrayia [7]

Answer:

  1. The limiting reagent is N2O4
  2. 14,09g

Explanation:

  • First, we adjust the reaction.

2N_{2} H_{4} + N_{2} O_{4} ⇄6N_{2} +  4H_{2}O

  • Second, we assume that the participating moles are equal to the stoichiometric ratios because we do not know the amounts of the reagents.

We can determinate what is the limiting reagent comparing of product amounts which can be formed from each reactant.

Using N_{2} H_{4} to form H_{2}O

               molH_{2} O = 1mol N_{2} H_{4} } . \frac{4 mol H_{2} O}{2mol N_{2} H_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}H_{4}  }{32,04\frac{g}{mol}  N_{2} H_{4} }

                                           molH_{2} O = 1, 125 mol

Using N_{2} O_{4} to form H_{2} O

              molH_{2} O = 1mol N_{2} O_{4} } . \frac{4 mol H_{2} O}{1mol N_{2} O_{4} }. \frac{18\frac{g}{mol}  H_{2} O}{1mol H_{2} O_} } . \frac{ 1 mol N_{2}O_{4}  }{92\frac{g}{mol}  N_{2} O_{4} }

                                           molH_{2} O = 0,783 mol

The limiting reagent is N2O4, because can produce only 0, 783 mol of H2O.

This is the minimum measure can be formed of each product.

∴                          MassOfH_{2}O = 0,783mol . 18\frac{g}{mol}

                                      MassOfH_{2}O = 14,09g

5 0
4 years ago
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