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2 years ago

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jason and manuel wanted to separate sand from water in the space provided draw the set up required to obtain water from such a m

ixture name the method used and the label all apparatus in the set up

1 answer:

yuradex [85]2 years ago

5 0

Answer:

here is the answer, hope this helped!

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Which statement is true for one molecule of sulfur trioxide?A.(There are three atoms of sulfur and one atom of oxygen.B.(There a

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The density of lead is 11.3g/cm^3 and the density of chromium is 7.14g/cm^3. If we have one gram of each metal, what is the rati

Lady bird [3.3K]

The ratio of the volume of lead to the volume of chromium is 22 : 35

Density is simply defined as the mass of a substance per unit volume of the substance.

<h3>Density = mass / volume </h3>

To solve the question given above, we'll begin by calculating the volume of lead and chromium. This can be obtained as follow:

<h3>For Lead:</h3>

Mass of lead = 1 g

Density of lead = 11.3 g/cm³

<h3>Volume of lead =? </h3>

Density = mass /volume

11.3 = 1 / Volume

Cross multiply

11.3 × Volume = 1

Divide both side by 11.3

Volume = 1 / 11.3

<h3>Volume of lead = 0.088 cm³</h3>

<h3>For Chromium:</h3>

Mass of chromium = 1 g

Density of chromium = 7.14 g/cm³

<h3>Volume of chromium =? </h3>

Density = mass /volume

7.14 = 1 / Volume

Cross multiply

7.14 × Volume = 1

Divide both side by 7.14

Volume = 1 / 7.14

<h3>Volume of chromium = 0.14 cm³</h3>

Finally, we shall determine the ratio of the volume of lead to the volume chromium. This can be obtained as follow:

Volume of lead = 0.088 cm³

Volume of chromium = 0.14 cm³

<h3>Ratio of the volume of lead to chromium =? </h3>

Ratio = Volume of lead / Volume of chromium

Ratio = 0.088 / 0.14

Ratio = 22 / 35

<h3>Ratio = 22 : 35</h3>

Therefore, the ratio of the volume of lead to the volume chromium is 22 : 35

Learn more: brainly.com/question/17262276

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3 years ago

The following reaction is part of the electron transport chain. Complete the reaction and identify which species is reduced. The

Olegator [25]

Answer:

$FADH_2 + Q --> FAD + QH_2$

The reactant that is reduced is $FADH_2$

Explanation:

The complete equation is as below:

$FADH_2 + Q --> FAD + QH_2$

<em>Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.</em>

In the above reaction, $FADH_2$ loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to $QH_2$ , hence the reducing agent.

<u>In order words, </u> $FADH_2$ <u> is reduced while coenzyme Q is oxidized.</u>

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3 years ago