Ask question

Ask question

All categories

2 years ago

14

jason and manuel wanted to separate sand from water in the space provided draw the set up required to obtain water from such a m

ixture name the method used and the label all apparatus in the set up

1 answer:

yuradex [85]2 years ago

5 0

Answer:

here is the answer, hope this helped!

You might be interested in

Estimate the surface-to-volume ratio of a C60 fullerene by treating the molecule as a hollow sphere and using 77pm for the atomi

AleksAgata [21]

Answer:

The surface-to-volume ratio of a C-60 fullerene is 3:77.

Explanation:

Surface area of sphere = $S=4\pi r^2$

Volume of the sphere = $V=\frac{4}{3}\pi r^3$

where : r = radius of the sphere

Radius of the C-60 fullerene sphere = r = 77 pm

Surface area of the C-60 fullerene = $S=4\pi (77 pm)^2$ ...[1]

Volume area of the C-60 fullerene = $V=\frac{4}{3}\pi (77 pm)^3$ ..[2]

Dividing [1] by [2]:

$\frac{S}{V}=\frac{4\pi (77 pm)^2}{\frac{4}{3}\pi (77 pm)^3}$

$=\frac{3}{77}$

The surface-to-volume ratio of a C-60 fullerene is 3:77.

7 0

3 years ago

Mrs. Rushing has 3 chemistry classes with 24 students in each. An experiment calls for each student to use 4 test tubes. How man

stira [4]

If they have 3 chemistry classes with 24 students, than there are 72 students in total. Each student requires 4 test tubes. 72 * 4 = 288 test tubes. Our answer is C.) 288 test tubes

5 0

3 years ago

Read 2 more answers

If the Earth moved farther away from the sun, which of these would probably happen?

Margaret [11]

The climate would become colder...

7 0

3 years ago

Read 2 more answers

Calculate the no. of each atoms presents in 10 grams of calcium carbonate.

raketka [301]

Molar Mass of Calcium carbonate:-

$\\ \sf\longmapsto CaCO_3$

$\\ \sf\longmapsto 40u+12u+3(16u)$

$\\ \sf\longmapsto 52u+48u$

$\\ \sf\longmapsto 100u$

$\\ \sf\longmapsto 100g/mol$

Given Mass=10g

$\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}$

$\\ \sf\longmapsto No\:of\;moles=\dfrac{10}{100}$

$\\ \sf\longmapsto No\:of\:moles=0.1mol$

Now

$\boxed{\sf No\:of\:molecules=No\;of\:moles\times Avagadro\: No}$

$\\ \sf\longmapsto 0.1\times 6.023\times 10^{23}$

$\\ \sf\longmapsto 6.023\times 10^{22}molecules$

8 0

3 years ago

...................................................................

neonofarm [45]

Answer:

Imao ;/

Explanation:

5 0

3 years ago

Read 2 more answers