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Pie
4 years ago
8

Calculate the hydronium ion, [ H30+], and hydroxide ion, [OH-], concentrations for a

Chemistry
1 answer:
mixer [17]4 years ago
4 0

Answer:

[H3O+] = 0.0117 M

[OH-] = 8.5 * 10^-13 M

Explanation:

Step 1: Data given

Concentration of HCl = 0.0117 M

Step 2:

HCl is a strong acid

pH of a strong acid = -log[H+] = - log[H3O+]

[H3O+] = 0.0117 M

pH = -log(0.0117)

pH = 1.93

pOH =14 - 1.93 = 12.07

pOH = -log[OH+] = 12.07

[OH-] = 10^-12.07 = 8.5 * 10^-13

Or

Kw / [H3O+] = [ OH-]

10^-14 / 0.0117 = 8.5*10^-13

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The molar concentration of potassium ions in a  0. 250 m K₂SO₄(aq) solution is 2.

<h3>What is molar concentration?</h3>

The molar concentration of a solution is the presence of solute in one unit of a solution.

Molar concentration = number of moles / volume

The volume is given 0.250 m

To calculate the number of moles:

There will be 2 moles of potassium and  1 mole of sulfate in one L of the solution.

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The total number of moles of potassium and sulfate ion are 0.500

Now, putting the value:

Molar concentration = number of moles / volume

0.500 / 0.250 = 2

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