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fiasKO [112]
3 years ago
12

18. If the pH of a strong acid solution is known to be 3.25, what is the [H+)?

Chemistry
1 answer:
Korolek [52]3 years ago
7 0
[H+] is 5.623*10^-4
2.poH is 10.75
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The reaction betwen aluminum and iron (III) oxide can
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Answer : The mass of Al_2O_3 formed will be, 468.18 grams.

Solution : Given,

Mass of Al = 124 g

Mass of Fe_2O_3 = 601 g

Molar mass of Al = 27 g/mole

Molar mass of Fe_2O_3 = 160 g/mole

Molar mass of Al_2O_3 = 102 g/mole

First we have to calculate the moles of Al and O_2.

\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{124g}{27g/mole}=4.59moles

\text{ Moles of }Fe_2O_3=\frac{\text{ Mass of }Fe_2O_3}{\text{ Molar mass of }Fe_2O_3}=\frac{601g}{160g/mole}=3.76moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe

From the balanced reaction we conclude that

As, 2 mole of Al react with 1 mole of Fe_2O_3

So, 4.59 moles of O_2 react with \frac{4.59}{2}=2.295 moles of Fe_2O_3

From this we conclude that, Fe_2O_3 is an excess reagent because the given moles are greater than the required moles and Al is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Al_2O_3

From the reaction, we conclude that

As, 2 mole of Al react to give 2 mole of Al_2O_3

So, 4.59 moles of O_2 react to give \frac{2}{2}\times 4.59=4.59 moles of Al_2O_3

Now we have to calculate the mass of Al_2O_3

\text{ Mass of }Al_2O_3=\text{ Moles of }Al_2O_3\times \text{ Molar mass of }Al_2O_3

\text{ Mass of }Al_2O_3=(4.59moles)\times (102g/mole)=468.18g

Therefore, the mass of Al_2O_3 formed will be, 468.18 grams.

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