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Vinil7 [7]
3 years ago
12

If the side lengths of a Triangle are: 2t, t, 3t, and the perimeter is equal to 60 meters; what is the value of t? a 20 b 12 c 1

0 d 6
Mathematics
2 answers:
kati45 [8]3 years ago
7 0

Answer:

the answer is 10

Step-by-step explanation:

2 x 10 = 20... T x 10 = 10..... 3 x 10 = 30... 30 +20+10 equals 60

miv72 [106K]3 years ago
6 0

Answer:

x equals 10

Step-by-step explanation:

so so you if the perimeter is 60 and when you measure perimeter you add up all these sides so you would add 2t + t + 3t = 60 then you would divide by 6 and get 10.

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densk [106]

Answer:

A.\ y = x^2 - 6x + 13 is the correct answer.

Step-by-step explanation:

We know that vertex equation of a parabola is given as:

y = a(x-h)^2+k

where (h,k) is the vertex of the parabola and

(x,y) are the coordinate of points on parabola.

As per the question statement:

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Let a = +1

Minimum of parabola is at x = 3.

The vertex is at the minimum point of a parabola that opens upwards.

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Putting value of a and h in the equation:

y = 1(x-3)^2+k\\\Rightarrow y = (x-3)^2+k\\\Rightarrow y = x^2-6x+9+k

Formula used: (a-b)^2=a^{2} +b^{2} -2\times a \times b

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Please refer to the graph attached.

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3 0
3 years ago
Read 2 more answers
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