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Margarita [4]
3 years ago
15

write the chemical equation for the following reaction: the elements carbon and oxygen combine to yield the compound carbon diox

ide
Chemistry
1 answer:
sergejj [24]3 years ago
7 0
Carbon + oxygen ---> carbon dioxide

C + O ---> CO2 
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CHEMISTRY HELP! Lewis structure rules<br><br> Please help, is this correct?
fiasKO [112]

Answer:

it is the one below that. NO, because it debt net the octet rule

4 0
3 years ago
If 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy __________ L at STP.
Vlad [161]

If 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy 25.48 L at STP.

<h3>How to calculate volume?</h3>

The volume of a gas at STP can be calculated using the direct proportion method.

According to this question, 50.75 g of a gas occupies 10.0 L at STP, then 129.3g of the same gas will occupy the following:

= 129.3 × 10/50.75

= 25.48L

Therefore, if 50.75 g of a gas occupies 10.0 L at STP, 129.3 g of the gas will occupy 25.48 L at STP.

Learn more about volume at: brainly.com/question/12357202

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6 0
2 years ago
1. Which is not true of binary compounds?
nignag [31]
Pretty sure it's b but not an definitely
4 0
3 years ago
Read 2 more answers
Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling
Reil [10]

Answer:

The boiling  point of a 8.5 m solution of Mg3(PO4)2 in water is<u> 394.91 K.</u>

Explanation:

The formula for molal boiling Point elevation is :

\Delta T_{b} = iK_{b}m

\Delta T_{b} = elevation in boiling Point

K_{b} = Boiling point constant( ebullioscopic constant)

m = molality of the solution

<em>i =</em> Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

<em>i =</em> Van't Hoff Factor = 5

m = 8.5 m

K_{b} = 0.512 °C/m

Insert the values and calculate temperature change:

\Delta T_{b} = iK_{b}m

\Delta T_{b} = 5\times 0.512\times 8.5

\Delta T_{b} = 21.76 K

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

\Delta T_{b} = T_{b} - T_{b}_{pure}

T_{b}_{pure} = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

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3 years ago
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B, turns red litmus paper to blue
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