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pentagon [3]
4 years ago
13

How many mole of ZnCl2 will be produced from 55.0 g of Zn, assuming HCL is available in excess

Chemistry
1 answer:
Ilia_Sergeevich [38]4 years ago
8 0

Answer:

0.84 mol

Explanation:

Given data:

Moles  of ZnCl₂ produced = ?

Mass of Zn = 55.0 g

Solution:

Chemical equation:

2HCl + Zn  →  ZnCl₂ + H₂

Number of moles of Zn:

Number of moles = mass / molar mass

Number of moles = 55.0 g/ 65.38 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of Zn with ZnCl₂ from balance chemical equation.

                                      Zn          :             ZnCl₂

                                         1          :               1

                                      0.84       :           0.84

So from 55 g of Zn 0.84 moles of zinc chloride will be produced.

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VashaNatasha [74]

Answer:

There is 18.8% lithium by mass in second sample

Explanation:

Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-

Let's assume weight of first sample is x g

So, 100 g of sample contains 18.8 g of lithium

Hence, x g of sample contains (\frac{18.8}{100}\times x) g of lithium

Now, the second sample has weight equal to 2x g

So, 2x g of sample contains (\frac{18.8}{100}\times 2x) g of lithium

So, % lithium by mass in second sample = (\frac{\frac{18.8}{100}\times 2x}{2x})\times 100 % = 18.8%

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