Math help mee plzzzzzz THERE IS A ATTACHMENT SO WAIT AT LEAST 30 SECONDS PLZZZZ
2 answers:
10. 2800 = 500 + 2x
-500 -500
2x = 2300
/2 /2
x = 1150
the cost for one month is $1150
11. 20-3h=2
-20 -20
-3h = -18
/-3 /-3
h = 6
12. g/7-15=-12
+15 +15
g/7=3 >> (7/1)*(g/7) = 3(7)
g = 21
13. 17= p-3-3p
2p-3=17
+3 +3
2p = 20
/2 /2
p = 10
14. -4(r+6)=-63 (distribute)
-4r-24=-63
+24 +24
-4r = 39
/-4 /-4
r = -9 3/4
15. 4x+3(x-2)=-20
4x+3x-6=-20
+6 +6
7x = -14
/7 /7
x = -2
16. 3n-5=7n+11
-3n -3n
7n-11=-5
+11 +11
7n = 6
/7 /7
n = 6/7
17. -6a+3=-3(2a-1)
/-3 /-3
-2a+1=-2a+1
+2a-1 +2a-1
0 = 0
18. 2y+5=1/2(4y+8) >> multiply both sides by 2/1
2(2y+5)=4y+8
4y+10=4y+8
-4y -4y
10
8
-500 -500
2x = 2300
/2 /2
x = 1150
the cost for one month is $1150
11. 20-3h=2
-20 -20
-3h = -18
/-3 /-3
h = 6
12. g/7-15=-12
+15 +15
g/7=3 >> (7/1)*(g/7) = 3(7)
g = 21
13. 17= p-3-3p
2p-3=17
+3 +3
2p = 20
/2 /2
p = 10
14. -4(r+6)=-63 (distribute)
-4r-24=-63
+24 +24
-4r = 39
/-4 /-4
r = -9 3/4
15. 4x+3(x-2)=-20
4x+3x-6=-20
+6 +6
7x = -14
/7 /7
x = -2
16. 3n-5=7n+11
-3n -3n
7n-11=-5
+11 +11
7n = 6
/7 /7
n = 6/7
17. -6a+3=-3(2a-1)
/-3 /-3
-2a+1=-2a+1
+2a-1 +2a-1
0 = 0
18. 2y+5=1/2(4y+8) >> multiply both sides by 2/1
2(2y+5)=4y+8
4y+10=4y+8
-4y -4y
10
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Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
_____
* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
