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2 years ago

Math help mee plzzzzzz THERE IS A ATTACHMENT SO WAIT AT LEAST 30 SECONDS PLZZZZ

Mathematics

2 answers:

Bas_tet [7]2 years ago

8 0

10. 2800 = 500 + 2x
-500 -500
2x = 2300
/2 /2

x = 1150
the cost for one month is $1150

11. 20-3h=2
-20 -20

-3h = -18
/-3 /-3

h = 6

12. g/7-15=-12
+15 +15
g/7=3 >> (7/1)*(g/7) = 3(7)

g = 21

13. 17= p-3-3p
2p-3=17
+3 +3
2p = 20
/2 /2

p = 10

14. -4(r+6)=-63 (distribute)
-4r-24=-63
+24 +24

-4r = 39
/-4 /-4

r = -9 3/4

15. 4x+3(x-2)=-20
4x+3x-6=-20
+6 +6

7x = -14
/7 /7

x = -2

16. 3n-5=7n+11
-3n -3n

7n-11=-5
+11 +11

7n = 6
/7 /7

n = 6/7

17. -6a+3=-3(2a-1)
/-3 /-3

-2a+1=-2a+1
+2a-1 +2a-1

0 = 0

18. 2y+5=1/2(4y+8) >> multiply both sides by 2/1
2(2y+5)=4y+8

4y+10=4y+8
-4y -4y

10 $\neq$ 8

yarga [219]2 years ago

4 0

I hope this helps you

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What’s the value of x? :/

kolbaska11 [484]

Answer:

$x = 27$

Step-by-step explanation:

According to congruent chords and arcs theorem, if $\overline{XY} \cong \overline{ZY}$ then $\arc{XY} \cong \arc{ZY}$ .

This means that $\arc{XY} = \arc{ZY} = (6x - 20) degrees$

Thus:

$\arc{XY} + \arc{ZY} + \arc{ZX} = 360$ (full circle = 360°)

$\arc{XY} = (6x - 20)$

$\arc{ZY} = (6x - 20)$

$\arc{ZX} = 76$

Plug in the values into the equation

$(6x - 20) + (6x - 20) + 76 = 360$

$6x - 20 + 6x - 20 + 76 = 360$

Add like terms

$12x + 36 = 360$

Subtract 36 on both sides

$12x = 360 - 36$

$12x = 324$

Divide both sides by 12

$x = 27$

8 0

3 years ago

The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the

vagabundo [1.1K]

Let $L$ be the length of the rectangle and $W$ be the width. In the problem it is given that $L=2W-3$ . It is also given that the area $LW=27$ . Substituting in the length in terms of width, we have $W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0$ . Using the zero product property, $2W-9=0 \text{ or } W+3=0$ . Solving these we get the width $W=4.5 \text{ or } -3$ . However, it doesn't make sense for the width to be negative, so the width must be $\boxed{4.5 \text{ m}}$ . From that we can tell the length $L=2(4.5)-3=\boxed{6 \text{ m}}$ .