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3 years ago

What is the resultant of a and b if a = 3i 3j and b = 3i − 3j?

Physics

2 answers:

GrogVix [38]3 years ago

6 0

Answer:

Resultant, $R=6i$

Explanation:

Given that,

Vector $A=3i+3j$

Vector $B=3i-3j$

Vectors are those quantities that have both magnitude and direction. We need to find the resultant A and B. It can be done by adding two vectors such that,

$R=A+B$

$R=(3i+3j)+(3i-3j)$

$R=6i$

So, the resultant of A and B is 6i. Hence, this is the required solution.

ss7ja [257]3 years ago

3 0

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3 years ago

Assuming that the limits of the visible spectrum are approximately 380 and 700 nm, find the angular range of the first-order vis

ch4aika [34]

Answer:

angular range is ( 0.681 rad , 0.35 rad )

Explanation:

given data

wavelength λ = 380 nm = 380 × $10^{-9}$ m

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to find out

angular range of the first-order

solution

we will apply here slit experiment equation that is

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so put here value in equation 1 for 380 nm

we get

d sinθ = m λ

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θ = 0.35 rad

and for 700 nm

we get

d sinθ = m λ

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θ = 0.681 rad

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3 0

3 years ago

What is the change in length of a 1400. m steel, (12x10^-6)/(C0) , pipe for a temperature change of 250.0 degrees Celsius? Remem

8090 [49]

Answer:

$\Delta L = 4.2 m$

Explanation:

As per the formula of thermal expansion we know that

$L = L_o(1 + \alpha\Delta T)$

so here we will have

$L_o = 1400 m$

$\alpha = 12 \times 10^{-6} per ^oC$

$\Delta T = 250 degree C$

so here change in the length of the rod is given as

$\Delta L = L - L_o$

$\Delta L = L_o \alpha \Delta T$

$\Delta L = 1400 (12 \times 10^{-6})(250)$

$\Delta L = 4.2 m$

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3 years ago