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3 years ago

What is the resultant of a and b if a = 3i 3j and b = 3i − 3j?

Physics

2 answers:

GrogVix [38]3 years ago

6 0

Answer:

Resultant, $R=6i$

Explanation:

Given that,

Vector $A=3i+3j$

Vector $B=3i-3j$

Vectors are those quantities that have both magnitude and direction. We need to find the resultant A and B. It can be done by adding two vectors such that,

$R=A+B$

$R=(3i+3j)+(3i-3j)$

$R=6i$

So, the resultant of A and B is 6i. Hence, this is the required solution.

ss7ja [257]3 years ago

3 0

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The diagram below represents a flashlight that has been turned on. Which form of energy is being converted to electrical energy

Orlov [11]

Answer:

Chemical energy to electrical energy

Explanation:

In nature, there are several types of energy.

In this example (a flashlight being turned on), we have a conversion of energy from chemical energy to electrical energy. In fact:

- Chemical energy is the energy stored in the chemical bonds of the molecules of the substances used inside the battery. When the chemical reaction inside the battery occurs, this energy is liberated, and it is used to "push" the electrons along the circuit connected to the battery

- Electric energy is the energy associated to the motion of the electrons along the circuit of the flashlight; it is the energy associated to an electric current.

Moreover, in the flashlight the electric energy is then converted into two more types of energy: light energy (since the bulb in the flashlight produces light) and heat energy (because the flashlight also produces heat, so thermal energy).

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3 years ago

What type of friction prevents a pile of rocks from falling apart?

BlackZzzverrR [31]

A because it some type of friction

6 0

2 years ago

g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?

beks73 [17]

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

$F = \sqrt{F_x^2 + F_y^2}$

$F = \sqrt{5.69^2 + 8^2}$

$F = \sqrt{32.3761 + 64}$

$F = \sqrt{96.3761}$

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

4 0

3 years ago

Read 2 more answers

A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 35.5 m/s. a) What is the coeff

postnew [5]

Answer:

The coefficient of friction present between the roadway and the wheels of the truck is <u>0.833</u>.

Explanation:

Given:

Radius of the curve (R) = 150 m

Maximum speed of truck (v) = 35.5 m/s

Let the coefficient of friction between the roadway and the wheels of the truck be "μ".

As the truck is moving around a circular curve. So, the force acting on it is centripetal force which acts in the radial inward direction towards the center of the circular curve.

The centripetal force acting on the truck is given as:

$F_c=\frac{mv^2}{R}$

Now, the friction between the roadway and the wheels of the truck is responsible for providing the necessary centripetal force. So, frictional force is equal to the centripetal force necessary for circular motion.

Frictional force is given as:

$f=\mu N$

Where, 'N' is the normal force. Since there is no vertical motion, the normal force is equal to weight of truck. So,

$N=mg$

Therefore, frictional force, $f=\mu mg$

Now, frictional force = centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu = \frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu=\frac{(35\ m/s)^2}{(150\ m)(9.8\ m/s^2)}\\\\\mu=\frac{1225\ m^2/s^2}{1470\ m^2/s^2}\\\\\mu=0.833$

Therefore, the coefficient of friction present between the roadway and the wheels of the truck is 0.833

7 0

3 years ago

Recessed incandescent luminaires not marked type ic and those marked for installing directly in ___________ must not have insula

slavikrds [6]

Answer:

Recessed incandescent luminaires not marked type ic and those marked for installing directly in insulated ceilings must not have insulation over the top of the luminaire.

Explanation:

Depending on how they interact with insulation, lighting fixtures are rated at various levels. Non-IC rated lighting fixtures can accommodate higher wattage bulbs, but they also pose the greatest fire risk when used with the incorrect insulation.

In locations with insulation, light fixtures that are not IC rated may be installed. But there is a condition. The distance between the fixture and any insulation should be 3 inches. But the 3 inch gap in the insulation would negate the goal of insulation by producing a lot of uninsulated space, so this defies logic. Building a box-style cover to cover the fixture on the attic side is one option to fix this. Drywall or foil-faced foam insulation can be used to create this box. After the cover is put in place, insulation can be added for maximum effectiveness.

To learn more about recessed incandescent luminaries. Click brainly.com/question/17218799

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6 0

1 year ago