The moment of inertia of when it is rotated around the -axis .
Solution:
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Consider a line that passes through the center of the ring and is perpendicular to the plane of the ring. Let R be the radius of the ring and M be its mass. All elements are at the same distance from the axis of rotation. The moment of inertia formula is the sum of the mass products of each particle multiplied by the square of the distance from the axis of rotation.
Moments of inertia oppose the rotational motion, so they are called moments of inertia rather than moments of force. A moment of inertia is defined with respect to a particular axis of rotation. The moment of inertia of a mass with respect to an axis is defined as the square of the mass times the distance from the axis.
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Answer:
Explanation:
Relation between Celsius and Kelvin is
K = C + 273
Relation between Kelvin and Fahrenheit is
(a) 379 K
Relation between Celsius and Kelvin is
K = C + 273
So, C = K - 273 = 379 - 273 = 106
Thus, 379 K = 106°C.
(b) 379 K
Relation between Kelvin and Fahrenheit is
F = 222.8°F
Thus, 379 K = 222.8°F
(c) 1.04 x 10^2 K = 104 K
Relation between Celsius and Kelvin is
K = C + 273
So, C = K - 273 = 104 - 273 = -169
Thus, 104 K = - 169°C.
(d) 1.04 x 10^2 K = 104 K
Relation between Kelvin and Fahrenheit is
F =- 272.2°F
Thus, 104 K = - 272.2°F
Answer:
Explanation:
The expression which represent the first diffraction minima by a circular aperture is given by --------eqn 1
The angle through which the first minima is diffracted is given by ---------eqn 2
As is very small so we can write
So from eqn 1 and eqn 2 we can write
--------eqn 3
Here is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture
It is given that diameter of circular aperture is 14.7 cm so
Now putting all these value in eqn 3
Answer:
Explanation:
<u>Given:</u>
velocity of the ball first and ball second,
angle of projection of the first ball,
∵The balls should land at the same point,
∴their range of projectile,
As we know for the range of projectile:
∵ we have equal range in both the cases
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