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wolverine [178]
4 years ago
10

Select the correct statement to describe when a sample of liquid water vaporizers into water vapor

Physics
1 answer:
AnnyKZ [126]4 years ago
4 0
From what I know; When a sample of liquid water vaporizes into water vapor, the electrons in the water sped up due to heat. 
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Cause it reflects i think so
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3 years ago
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If we decrease the size of a quantum dot that contains an electron, what happens to the energy levels?
Law Incorporation [45]

We will solve this problem using the direct concept related to band gap energy, that is, a band gap is the distance between the valence band of electrons and the conduction band, i. e, the energy range in a solid where no electron states (Electronic state) can exist Mathematically can be described as,

E_n = \frac{h^2n^2}{8mcR^2}

Where,

h = Planck's constant

n = Energy level

mc = Effective mass of the point charge

R = Size of the particle

As you can see the energy is inversely proportional to the size of the particle:

E_n \propto \frac{1}{R^2}

Therefore if the size is decreased, the amount of energy is increased.

6 0
3 years ago
State Newtons first law of motion.
Fofino [41]

Answer:

An object at rest will stay at rest and an object in motion will stay in motion unless it is acted upon by an unbalanced/external force.

8 0
4 years ago
How fast does a 2 MeV fission neutron travel through a reactor core?
Artemon [7]

Answer:

The answer is 1.956 \times 10^7\ m/s

Explanation:

The amount of energy is not enough to apply the relativistic formula of energy E = mc^2, so the definition of energy in this case is

E = \frac{1}{2}m v^2.

From the last equation,

v= \sqrt{2E/m}

where

E = 2 MeV = 3.204 \times 10^{-13} J

and the mass of the neutron is

m = 1.675\times 10^{-27}\ Kg.

Then

v = 1.956 \times 10^7\ m/s

the equivalent of 0.065 the speed of light.

5 0
3 years ago
Two point charges, with charge magnitudes q and ????, are placed a distance r apart. In this arrangement, each point charge expe
sammy [17]

Answer:

1)  Q ’= 8 Q ,  2)    q ’= 16 q ,  3)   r ’= ¾ r

Explanation:

For this exercise we will use Coulomb's law

      F = k q Q / r²

It asks us to calculate the change of any of the parameters so that the force is always F

Original values

                q, Q, r

Scenario 1

      q ’= 2q

       r ’= 4r

     F = k q ’Q’ / r’²

we substitute

     F = k 2q Q ’/ (4r)²

     F = k 2q Q '/ 16r²

we substitute the value of F

      k q Q / r² = k q Q '/ 8r²

       Q ’= 8 Q

Scenario 2

       Q ’= Q

       r ’= 4r

we substitute

      F = k q ’Q / 16r²

      k q Q / r² = k q’ Q / 16 r²

      q ’= 16 q

Scenario 3

      q ’= 3/2 q

      Q ’= ⅜ Q

we substitute

        k q Q r² = k (3/2 q) (⅜ Q) / r’²

        r’² = 9/16 r²

        r ’= ¾ r

6 0
4 years ago
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