1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
konstantin123 [22]
3 years ago
11

A 5.0 c charge is 10 m from a small test charge. what is the magnitude of the electric field at the location of the test charge

?
Physics
1 answer:
Inessa [10]3 years ago
7 0

Answer:

4.50*10^8\frac{N}{C}

Explanation:

The electric field is generated by a charge and represents the force exerted on a test charge, that is, the electric force per unit of charge. Therefore the equation for the electric field can be obtained from Coulomb's law.

E=\frac{F}{q}\\E=\frac{kq}{r^2}\\E=\frac{5C*8.99*10^9\frac{Nm^2}{C^2}}{(10 m)^2}=4.50*10^8\frac{N}{C}

You might be interested in
(a) Draw a Velocity - Time graph for an Object with Constant Acceleration.
den301095 [7]

Explanation:

answers to 1 and 2 above/below respectively but can't do 3 because I don't know what graph you're talking about

7 0
2 years ago
Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 3.3 cm . Two of
sweet [91]

Answer:

1.44\times 10^{-3} N

Explanation:

We are given that three charged particle are placed at each corner  of equilateral triangle.

q_1=-8.2 nC,q_2=-16.4 nC,q_3=8.0nC

q_1=-8.2\times 10^{-9} C

q_2=-16.4\times 10^{-9} C

q_3=8.0\times 10^{-9} C

Side of equilateral triangle =3.3 cm=\frac{3.3}{100}=0.033m

We know that each angle of equilateral angle=60^{\circ}

Net force=F =\sum\frac{kQq }{d^2}

Where k=9\times 10^9 Nm^2/C^2

If we bisect the angle at q_3 then we have 30 degrees from there to either charge.

Direction of vertical force  due to charge q_1 and q_2

Therefore, force will be added

Vertical  force=9\times 10^9\times q_3(q_1+q_2)\frac{cos30}{(0.033)^2})

Vertical net force=9\times 10^9\times 8\times 10^{-9}(-8.2-16.4)\times 10^{-9}\times 10^6\times\frac{\sqrt3}{2\times 1089}

Vertical  force =9\times 8(-24.6)\times 10^{-9}\times 10^6\times 1.732\times \frac{1}{2178}

Vertical  force=-1.41\times 10^{-3}N (towards q_1}

Horizontal component are opposite in direction then will b subtracted

Horizontal force=9\times 10^9\times 8\times 10^{-9}(-8.2+16.4) \times 10^{-9}\times \frac{sin30}{(0.033)^2}

Horizontal force=0.27\times 10^-3} N(towards q_2

Net electric force acting on particle 3 due to particle =\sqrt{F^2_x+F^2_y}

Net force=\sqrt{(-1.41\times 10^{-3})^2+(0.27\times 10^{-3})^2}

Net force=1.44\times 10^{-3} N

3 0
3 years ago
The centre of mass of a metre rule is at the 50cm mark. state what is meant by Centre of mass​
Tanya [424]

Answer:

Centre of mass of any body is a point where all mass of a body is supposed to be concentrated

it lies in geometrical centre....

3 0
3 years ago
The temperature at a point (x, y) on a flat metal plate is given by T(x, y) = 54/(7 + x2 + y2), where T is measured in °C and x,
ANTONII [103]

Answer:

dt/dx = -0.373702

dt/dy =  -1.121107

Explanation:

Given data

T(x, y) = 54/(7 + x² + y²)

to find out

rate of change of temperature with respect to distance

solution

we know function

T(x, y) = 54 /( 7 + x² + y²)

so derivative it x and y direction i.e

dt/dx = -54× 2x / (7 +x² + y²)²    .........................1

dt/dy = -54× 2y / (7 + x² + y²)²      .........................2

now put the value point (1,3) as x = 1 and y = 3 in equation 1 and 2

dt/dx = -54× 2(1) / (7 +(1)² + (3)²)²  

dt/dx = -0.373702

and

dt/dy =  -54× 2(3) / (7 + (1)² + (3)²)²

dt/dy =  -1.121107

7 0
3 years ago
In a drill during basketball practice, a player runs the length of the 30-meter court and back. The player does this three times
Sergeeva-Olga [200]

Answer:

0 m/s

Explanation:

Average velocity of an object is given by the net displacement divided by time taken. Displacement is equal to the shortest path covered by the object.

In this problem, a player runs the length of the 30-meter court and back. The player does this three times in 60 seconds.

As the player runs the court and returns to the original point. It would mean that the shortest path covered is 0.

Average velocity = displacement/time

v=0/30

v = 0 m/s

Hence, the correct option is (1).

6 0
3 years ago
Other questions:
  • A twig from a tree drops from a 200m high cliff on to a beach below.during its fall 40% twig's energy is converted into thermal
    10·1 answer
  • Which of the following is not a necessary condition for seeing a magnified image with a
    9·1 answer
  • 1. What quantity of heat is required to raise
    14·1 answer
  • For a person with a Near Point (NP) = 45 cm, what would be his prescription's lens power = _____________ diopters. A) 0.947368 d
    10·1 answer
  • A thermogram identifies the warm and cool parts of an object by using__________.
    5·1 answer
  • Help!! Urgent!! What property determines the sequence of layers in the earth?
    6·1 answer
  • You are cooking breakfast for yourself and a friend using a 1,140-W waffle iron and a 510-W coffeepot. Usually, you operate thes
    15·1 answer
  • A weightlifter lifts a 100-kg weight 1.5 meters off the floor at a constant velocity. Which statement about this situation is tr
    7·2 answers
  • A dog is running. His human calls to him and he accelerates at 2.74 m/s/s. 3.63 seconds later, his velocity is 10.3 m/s. What wa
    12·1 answer
  • A race car goes around a level, circular track with a diameter of 1.00 km at a constant speed of 95 km/h. What is the car's cent
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!