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Aleonysh [2.5K]
2 years ago
12

Which of the following can be used to induce abortion non surgically?

Physics
2 answers:
SSSSS [86.1K]2 years ago
7 0
The answer is C.Mifepristone
Julli [10]2 years ago
6 0
The answer is C.

Hope This Helps You!
Good Luck Studying :)
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Calculate the potential energy of 5.0g (0.005 kg) paper airplane 5.0 meters above the ground
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3 years ago
A 11.3-kg object oscillates at the end of a vertical spring that has a spring constant of 2.20 ✕ 104 N/m. The effect of air resi
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Answer:

(a) the frequency of the dampened oscillation is 7.02 Hz

(b) percentage decrease in amplitude of the oscillation in each cycle is 2%

Explanation:

Given;

mass of the object = 11.3 kg

the spring constant = 2.2 X 10⁴ N/m.

damping coefficient b = 3.00 N · s/m

Part (a) the frequency of the dampened oscillation

The oscillation frequency is calculated as follows;

\omega _D = \sqrt{\omega_o^2 -(\frac{b}{2m})^2}\\\\\omega_o^2 = \frac{k}{m} =\frac{2.2X10^{4}}{11.3} = 1946.903rad/s\\\\thus, \omega _D = \sqrt{1946.903-(\frac{3}{2*11.3})^2} =44.12 rad/s

The damped frequency = \frac{\omega _D}{2\pi } =  \frac{44.12}{2\pi } = 7.02 Hz

Part (b)  percentage decrease in amplitude of the oscillation in each cycle

The amplitude of the oscillation depends on the damping coefficient (b) and period (T), and it is given as;

A(t) = e^{-\frac{b}{2m}(t)}

After one cycle, the amplitude changes from A(t) to A(t+T), where T is the period of the oscillation.

A(t +T) = e^{-\frac{b}{2m}(t+T)}

Percentage decrease in amplitude is gotten by dividing A(t) by A(t+T)

= \frac{e^{-\frac{b}{2m}(t)}}{e^{-\frac{b}{2m}(t+T)}} =e^{-\frac{b}{2m}(T)}

But T = 1/f

Substituting the values of the parameters in the above equation, we will have;

=e^{-\frac{b}{2m}(T)} = e^{-\frac{3}{2X11.3}(\frac{1}{7.02})} = 0.98

Percentage decrease = 1 - 0.98 = 0.02 = 2%

4 0
3 years ago
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