Answer: (A) 780J
(B) 1.89×10^-11L
(C)1.67×10^-4 h
Explanation:
Energy of the battery = IVt
=13×60 = 780J
Heat combustion of
1g of gasoline relax 46000J
Therefore 780J will release 780/46000
= 0.017g
Density = mass/volume
Volume = mass/density
Volume =0.017× 10^-3 / 900
= 1.89× 10^-8 m3
= 1.89×10^-11 litres
P=IVt
t=P/IV
= 450/60×13
1.67×10^-4 hours
<span>For a particle moving in the +y and in a -x B field the force will be in the + z direction
Magnitude = q*v*B = 1.60 x 10^-19*1930*2.04 x 10^-3 = 0.63x10^-18N
a) the electric field creates a force = E*q in the +z direction
Fe = 4.27*1.60x10^-19 = 6.83 x 10^-19N
So F = 0.63 x 10^-18 + 6.83 x 10^-19 = 1.31 x 10^-18N
b) Now F = 0.63 x 10^-18 – 6.83 x 10^-19 = 0.5 x 10^-19N
c) Now add them as vectors so
F = sqrt((0.63 x 10^-18)^2 + (6.83 x 10^-19)^2) = 0.86 x 10^-18N</span>