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labwork [276]
3 years ago
8

Although wave power does not produce pollution, some people may not want to invest in it because it is _____. 100 percent renewa

ble inexpensive to operate low tech prone to storm damage and limited to particular areas of the ocean
Physics
2 answers:
notka56 [123]3 years ago
6 0
In my view, correct answer should look like this: Although wave power does not produce pollution, some people may not want to invest in it because it is <span>prone to storm damage and limited to particular areas of the ocean.</span>
exis [7]3 years ago
3 0

Answer

Correct answer is prone to storm damage

Explanation

Although wave power does not produce pollution, some people may not want to invest in it because It is prone to storm damage.

wave power in early stage early stages of development. Its can be setup in ocean or sea only and it can be damaged by high energy waves.Some waves are so strong that can destroy this power station easily.

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to shield domestic markets from foreign competition.

Explanation:

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Read 2 more answers
If a 9 V battery with 4 Ω contact resistance is used and the relay has 80 Ω and the wire has 10 Ω/mile, what is the maximum tele
Sedaia [141]

Answer:

Telegraph distance will be 9.6 mile

Explanation:

We have given the voltage V = 9 volt

Contact resistance = 4 ohm

Relay resistance = 80 ohm

And wire has a resistance = 10 ohm/mile

We have given the current = 50 mA =0.05 A

According to ohm's law R=\frac{V}{I}=\frac{9}{0.05}=180ohm

So the resistance of wire = 180-4-80=96 ohm

So the length of the telegraph distance will be \frac{96}{10}=9.6mile

4 0
4 years ago
A force of 500 N acting on an object of 2 kg displaces it by 3 m. Find the work done by the force and the object's final speed a
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3 years ago
Water flows through a water hose at a rate of Q1 = 860 cm3/s, the diameter of the hose is d1 = 1.85 cm. A nozzle is attached to
Snowcat [4.5K]

Answer:

a) A1 =  \frac{\pi (d1)^{2} }{4}

b) A1 = 2.688 cm^{2}

c) Q1 = A1 x v1

d) v1 = 3.1994 m/s

e) A2 = \frac{A1 X v1}{v2}

f)  A2 = 0.7963cm^{2}

Explanation:

a) Area = \pi r^{2}

r = \frac{d}{2}

thus,

area = \pi (\frac{d}{2})^{2}

A1 =  \frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 =  [tex]\frac{\pi (d1)^{2} }{4}

A1 =  \frac{\pi (1.85)^{2} }{4}

A1 = 2.688 cm^{2}

c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)

Q1 = A1 x v1

d) From the above equation,

v1 = \frac{Q1}{A1} = \frac{860}{2.688} = 319.94 cm/s = 3.1994 m/s

e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.

i.e. A1 x v1 = A2 x v2

thus,

A2 = \frac{A1 X v1}{v2}

f) v2 = 10.8 m/s.

substituting the values in the above equation,

A2 = \frac{2.688 X 3.1994}{10.8}  = 0.7963cm^{2}

3 0
4 years ago
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