<em>x = 3</em>
<em>y = 1</em>
- <em>Step-by-step explanation:</em>
<em>Hi ! </em>
<em>6x - 5y = 13</em>
<em>9y - 15 + 2x = 0</em>
<em />
<em>6x - 5y = 13</em>
<em>2x + 9y = 15 | ×(-3)</em>
<em />
<em>6x - 5y = 13</em>
<em>- 6x - 27y = - 45</em>
<em>add</em>
<em />
<em>6x - 6x - 5y - 27y = 13 - 45</em>
<em>- 32y = - 32 | ×(-)</em>
<em>32y = 32</em>
<em>y = 1</em>
<em>replace y = 1</em>
<em>6x - 5(1) = 13</em>
<em>6x - 5 = 13</em>
<em>6x = 13 + 5</em>
<em>6x = 18</em>
<em>x = 3</em>
<em>Good luck !</em>
<em />
Well since its specifically 1/6 what makes a whole? 1 does, So 6/6 would be one whole. Its literally 6 of 1/6 are in a whole.
Example: 1/6 2/6 3/6 4/6 5/6 6/6(<--- aka 1 whole)
Answer:9)B
10)C
Step-by-step explanation:
The guide can help you to learn how to do this yourself.
Answer: Option D
Step-by-step explanation:
Note that the projectile height as a function of time is given by the quadratic equation
To find the maximum height of the projectile we must find the maximum value of the quadratic function.
By definition the maximum value of a quadratic equation of the form
is located on the vertex of the parabola:
Where 
In this case the equation is:
Then
So:
FIRST ON IS THE RIGHT ANGLE AND THE SECOND ONE IS SUPPLEMENTARY
