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Viktor [21]
3 years ago
12

1. Calculate the total heat content of 10 kg of ice at -23°C.?

Physics
1 answer:
vesna_86 [32]3 years ago
8 0

To solve the problem, we must know the heat capacity of ice and water.

For Cp = 2090 J/kg C

H = mCpT

H = (10 kg) ( 2090 J/ Kg C) ( -23 C)

H = - 480700 J

For water Cp = 4180 j/kg C

H = (100 kg) ( 4180 J/kg C) ( 60 C)

<span>H = 2508000 J</span>

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Suppose that an electron and a positron collide head-on. Both have kinetic energy of 1.64 MeV and rest energy of 0.511 MeV. They
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Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
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total linear momentum before = linear momentum of first train car + linear momentum of second train car

We know that linear momentum = mv

where,

m = mass

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total linear momentum before = m₁v₁ + m₂v₂

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v₁ = velocity of first train car = 0.305m/s

m₂ = mass of first second car =  100,000kg

v₂ = velocity of second train car =  −0.210m/s

Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.

total linear momentum before = m₁v₁ + m₂v₂

                                                  = 135,000x0.305 + 100,000x(−0.210)

                                                  = 135,000x0.305 - 100,000x0.210

                                                  = 20,175 kgm/s

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total linear momentum before = total linear momentum after

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v =  \frac{20,175}{235,000}

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