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ohaa [14]
3 years ago
5

¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una

Physics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

La resistencia que debe ser conectada en paralelo con una de 20 Ω para hacer una  resistencia combinada de 15 Ω tiene un valor de 60 Ω

Explanation:

Las resistencias son aquellos dispositivos en los circuitos eléctricos que suelen emplearse para oponerse al paso de la corriente eléctrica.

Se denomina resistencia resultante o equivalente al valor de la resistencia que se obtiene al considerar un conjunto de ellas.

Cuando tenes resistencias en paralelo la corriente se divide y circula por varios caminos.

La resistencia equivalente de un circuito de resistencias en paralelo es igual al recíproco de la suma de los inversos de las resistencias individuales:

R=\frac{1}{\frac{1}{R_{1} } +\frac{1}{R_{2} } +...+\frac{1}{R_{N} }}

Esto también puede ser expresado como:

\frac{1}{R} =\frac{1}{R_{1} } +\frac{1}{R_{2} } +...+\frac{1}{R_{N} }

Entonces, en este caso sabes:

  • R= 15 Ω
  • R1= 20 Ω
  • R2=?

Reemplazando:

\frac{1}{15} =\frac{1}{20}+\frac{1}{R2}

y resolviendo:

\frac{1}{R2} =\frac{1}{15} -\frac{1}{20}

\frac{1}{R2} =\frac{1}{60}

se obtiene:

R2=60 Ω

<u><em>La resistencia que debe ser conectada en paralelo con una de 20 Ω para hacer una  resistencia combinada de 15 Ω tiene un valor de 60 Ω</em></u>

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Explanation:

There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.

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Separating the electron from the proton in a hydrogen atom takes 2.18 ✕ 10−18 j of work. through what electric potential differe
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A sand core used to form the internal surfaces of a steel casting experiences a buoyancy force of 225 n. the volume of the mold
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Newton’s second law gives us the relationship of force F, mass m and acceleration a. The formula is given as:

<span>F = m a                  --> 1</span>

However we also know that the relationship of mass m, density ρ, and volume V is:

<span>m = V ρ                 --> 2</span>

Therefore substituting equation 2 to equation 1:

F = ρ V a = ρ V g

where a is acceleration due to gravity, ρ is density of water and V is the volume of the casting, therefore:

F = (1x10^-3 kg/cm^3) (4840 cm^3) (9.8 m/s^2)

F = 47.432 kg m/s^2

F = 47.432 N

 

Going back to equation 1:

47.432 N = m (9.8 m/s^2)

m = 4.84 kg

 

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3 years ago
A hockey puck with mass 0.200 kg traveling east at 10.0 m/s strikes a puck with a mass of .250 kg heading north at 20 m/s and st
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Answer:

4.44 i + 11.11 j , 11.96 m/s

Explanation:

m1 = 0.2 kg, v1 = 10 m/s along X axis, v1 = 10 i

m2 = 0.25 kg, v2 = 20 m/s along north, v2 = 20 j

After collision they stick together and let they move with velocity v.

Use the conservation of momentum

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v = 4.44 i + 11.11 j

magnitude of velocity = \sqrt{(4.44)^{2}+(11.11)^{2}} = 11.96 m/s

Thus, the velocity of 0.250 kg hockey puck is 4.44 i + 11.11 j  metre per second and the magnitude of velocity is 11.96 m/s.

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