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9966 [12]
3 years ago
12

Suppose that 4 charged particles, all having a positive charge Q, are placed and fixed at the vertices of a square, where every

side has a length a.
(a) What is the electric potential at the center of this arrangement? You can use any of the symbols already provided to you when typing your answer, in addition to the symbol ke and any numbers. [NOTE: The symbol ke must be typed with e as a subscript on k to receive credit. Simply typing "ke" will not suffice.]
(b) Now imagine that we introduce a new charge, called q. How much potential energy would this charge have if it were placed at the center of the square? You can use any of the symbols already provided to you when typing your answer, in addition to the symbol ke and any numbers.PE =
Physics
1 answer:
algol [13]3 years ago
8 0

Answer:

+%_×¥+₩ £kshnow sjsni niadk lplz kfkd skidk skkkim

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Why do atoms do group 1 element lose electrons to form cations
Mrac [35]

Answer:

when a element of 1 group take part in reaction, its atom looses outer electron and form positively charged ions called Cation.

Explanation:

8 0
3 years ago
Which marine habitats would have the least access to primary producers?
nikitadnepr [17]

Answer:

D

Explanation:

4 0
2 years ago
A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
Stella [2.4K]

Answer:

Explanation:

mass of car, m1 = 1170 kg

mass of truck, m2 = 9800 kg

initial velocity of car, u1 = 25 m/s

initial velocity of truck, u2 = 20 m/s

final velocity of car, v1 = 18 m/s

Let the final velocity of truck is v2.

(a) Use the conservation of momentum

m1 x u1 + m2 x u2 + m1 x v1 + m2 x v2

1170 x 25 + 9800 x 20 = 1170 x 18 + 9800 x v2

29250 + 196000 = 21060 + 9800 v2

v2 = 20.84 m/s

(b) Total kinetic energy before collision,

Ki = 0.5 x 1170 x 25 x 25 + 0.5 x 9800 x 20 x 20

Ki = 365625 + 1960000 = 2325625 J

Total final kinetic energy

Kf = 0.5 x 1170 x 18 x 18 + 0.5 x 9800 x 20.84 x 20.84

Kf = 189540 + 2128097.44

Kf = 2317637.44 J

Change in energy = 2325625 - 2317637.44 = 7987.56 J

(c) It is due to the heat energy

4 0
4 years ago
If the primary to secondary voltage ratio is 4:1 for a transformer, what is the secondary voltage if the primary voltage is 460
Vesnalui [34]
<h2>The secondary voltage is 115 V.</h2>

Explanation:

The primary to secondary voltage ratio is given as 4:1 .

That is

                 \frac{V_p}{V_s}=\frac{4}{1}=4

We need to find what is the secondary voltage if the primary voltage is 460 volts.

That is

                    V_p=460V

Substituting in ratio equation

                    \frac{V_p}{V_s}=4\\\\\frac{460}{V_s}=4\\\\V_s=\frac{460}{4}\\\\V_s=115V

The secondary voltage is 115 V.                  

6 0
3 years ago
It's nighttime, and you've dropped your goggles into a 3.1-mm-deep swimming pool. If you hold a laser pointer 1.2 mm above the e
arlik [135]

Answer:

the googles are 4.33mm from the edge

Explanation:

In this question, we are asked to calculate the distance of a set of googles from the edge of a pool.

We proceed as follows;

depth of pool , d = 3.1mm

Now, let i be the angle of incidence

i = arctan(1.8/1.2)

i = 56.31 degree

Using snell's law ,

n1 * sin(i) = n2 * sin(r)

1 * sin(56.3) = 1.33 * sin(r)

r = 38.72 degrees

Now,

distance of googles = 1.8+ d*tan(r)

distance of googles = 1.8+ 3.1 * tan(38.72)

distance of googles = 4.3 mm

5 0
3 years ago
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