Question

A 0.410 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 35.0 pC charge on its surface. What is the potential (in V) near its surface

Answer 1

Answer:

The  potential is  $V = 153.659 \ V$

Explanation:

From the question we are told that

     The diameter of the plastic sphere is  $d = 0.410 \ cm = 0.0041 \ m$

      The magnitude of the charge is  $q = 35.0 pC = 35.0 *10^{-12} \ C$

The radius of the plastic sphere is  mathematically evaluated as

          $r = \frac{d}{2}$

=>     $r = \frac{0.0041}{2}$

       $r = 0.00205 \ m$

The  potential near the surface is mathematically represented as

         $V = \frac{k * q}{r }$

Where k is the Coulombs constant with value $9 *10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

substituting values  

       $V = \frac{9*10^9 * 35 *10^{-12}}{0.00205}$

       $V = 153.659 \ V$