Answer:
The force required to begin to lift the pole from the end 'A' is 240 N
Explanation:
The given parameters for the pole AB are;
The length of the pole, l = 10.0 m
The weight of the pole, W = 600 N ↓
The distance of the center of gravity of the pole from the side 'A' = 4.0 m
Let '
' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive
For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have
× 10.0 m - W × 4.0 m = 0
∴ × 10.0 m = W × 4.0 m = 600 N × 4.0 m
× 10.0 m = 600 N × 4.0 m
∴ = 600 N × 4.0 m/(10.0 m) = 240 N
The force required to begin to lift the pole from the end 'A', = 240 N.
Option B is correct. If an incident light ray hits a flat, smooth object at 28°. It will reflect off at an angle of 28°.
<h3>What is the law of reflection?</h3>
The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.
The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.
When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.
If an incident light ray hits a flat, smooth object at 28 degrees, it will reflect off at an angle of 28°.
Hence, option B is correct
To learn more about the law of reflection, refer to the link;
brainly.com/question/12029226
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Answer: Cold Ocean Currents: It is the layer of the ocean water which moves due to the stress of blowing the wind and this motion is thus called as Ekman Transport. Deep Water Currents: They constitute about 90% of the ocean water. They move around the ocean basin due to variations in the density and gravity.
Answer:
<h2>a)
Acceleration is 3.09 m/s²</h2><h2>
b) Distance traveled is 45.05 m</h2><h2>c)
Time taken to travel 250 m is 12.72 s</h2>
Explanation:
a) We have equation of motion v = u + at
Initial velocity, u = 0 km/hr = 0 m/s
Final velocity, v = 60 km/hr = 16.67 m/s
Time, t = 5.4 s
Substituting
v = u + at
16.67 = 0 + a x 5.4
a = 3.09 m/s²
Acceleration is 3.09 m/s²
b) We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 3.09 m/s²
Time, t = 5.4 s
Substituting
s = ut + 0.5 at²
s = 0 x 5.4 + 0.5 x 3.09 x 5.4²
s = 45.05 m
Distance traveled is 45.05 m
c) We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = 3.09 m/s²
Displacement, s = 0.25 km = 250 m
Substituting
s = ut + 0.5 at²
250 = 0 x t + 0.5 x 3.09 xt²
t = 12.72 s
Time taken to travel 250 m is 12.72 s
Answer: A. Object A will have a positive charge.
Explanation: If the number of protons and electrons are the same, their net charges cancel each other out, and you have a neutral charge. If electrons are transferred to another object, the amount of positive charge will outweigh the amount of negative charge. As a result, you are left with an overall positive charge in object A. Meanwhile, object B is now negative.
