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In-s [12.5K]
3 years ago
7

Topsoil is considered to be most fertile when it has a

Chemistry
2 answers:
anzhelika [568]3 years ago
5 0
It's D the answer is D
eduard3 years ago
4 0
I believe it is C, high organic matter level.
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Please help ASAP<br> Will give brainliest
Leni [432]

Answer:  457.8

Explanation:

345.8*225/703.55

8 0
2 years ago
In the following reaction, what element is gaining mass?
vagabundo [1.1K]

Mg gained mass because it went from being a single element (on the reactant side) to being a molecule (on the product side).

8 0
3 years ago
does girl code apply for when a girl dates her ex's friend. If not, is it wrong for the girl to do that (15 points)
andreev551 [17]

Answer:

Nope unless u like the ex it’s super wrong but if u like their friend ur good

Explanation:

6 0
3 years ago
Read 2 more answers
Be sure to answer all parts. Sulfur dioxide is released in the combustion of coal. Scrubbers use lime slurries of calcium hydrox
scoray [572]

<u>Answer:</u> The balanced chemical equation is written below and \Delta S^o for the reaction is -160.6 J/K

<u>Explanation:</u>

When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.

The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:

Ca(OH)_2(s)+SO_2(g)\rightarrow CaSO_3(s)+H_2O(l)

To calculate the entropy change of the reaction, we use the equation:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]

For the given reaction:

\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]

Taking the standard entropy change values:

\Delta S^o_{CaSO_3(s)}=101.4Jmol^{-1}K^{-1}\\\Delta S^o_{H_2O(l)}=69.9Jmol^{-1}K^{-1}\\\Delta S^o_{Ca(OH)_2(s)}=83.4Jmol^{-1}K^{-1}\\\Delta S^o_{SO_2(g)}=248.5Jmol^{-1}K^{-1}

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(1\times (101.4))+(1\times (69.9))]-[(1\times (83.4))+(1\times (248.5))]\\\\\Delta S^o_{rxn}=-160.6J/K

Hence, the balanced chemical equation is written above and \Delta S^o for the reaction is -160.6 J/K

3 0
3 years ago
How many moles of CCl4 are in 3.55L
marishachu [46]

Answer: 0.16 moles

Explanation: According to Avogadro's law, 1 mole of every gas at STP occupies a volume of 22.4 Liters.

Given: Volume occupied = 3.55 L

From Avogadro's law,

22.4 L of CCl_4 corresponds to= 1 mole

3.55 L of CCl_4 correspond to=\frac{1}{22.4}\times 3.55=0.16moles

6 0
3 years ago
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