Mg gained mass because it went from being a single element (on the reactant side) to being a molecule (on the product side).
Answer:
Nope unless u like the ex it’s super wrong but if u like their friend ur good
Explanation:
<u>Answer:</u> The balanced chemical equation is written below and
for the reaction is -160.6 J/K
<u>Explanation:</u>
When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.
The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:

To calculate the entropy change of the reaction, we use the equation:
![\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7Bproducts%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7Breactants%7D%5D)
For the given reaction:
![\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BCaSO_3%28s%29%7D%29%2B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BH_2O%28l%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BCa%28OH%29_2%28s%29%7D%29%2B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BSO_2%28g%29%7D%29%5D)
Taking the standard entropy change values:

Putting values in above equation, we get:
![\Delta S^o_{rxn}=[(1\times (101.4))+(1\times (69.9))]-[(1\times (83.4))+(1\times (248.5))]\\\\\Delta S^o_{rxn}=-160.6J/K](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%28101.4%29%29%2B%281%5Ctimes%20%2869.9%29%29%5D-%5B%281%5Ctimes%20%2883.4%29%29%2B%281%5Ctimes%20%28248.5%29%29%5D%5C%5C%5C%5C%5CDelta%20S%5Eo_%7Brxn%7D%3D-160.6J%2FK)
Hence, the balanced chemical equation is written above and
for the reaction is -160.6 J/K
Answer: 0.16 moles
Explanation: According to Avogadro's law, 1 mole of every gas at STP occupies a volume of 22.4 Liters.
Given: Volume occupied = 3.55 L
From Avogadro's law,
22.4 L of
corresponds to= 1 mole
3.55 L of
correspond to=