Which of the following is the end product of a natural radioactive series?
1 answer:
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Answer:
The answer to the questions are as follows
Reaction B is 4426.28 times faster than reaction A
(b) Reaction B is faster.
Explanation:
To solve the question we are meant to compare both reactions to see which one is faster
The values of the given activation energies are as follows
For A
Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and
for B
Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)
T is the same for both reactions and is equal to 298 k
Concentration of both reaction = 1M
The Arrhenius Law is given by
k =
Where
k = rate constant
Ea = activation energy
R = universal gas constant
T = temperature (Kelvin )
A = Arrhenius factor
Therefore
For reaction A, the rate constant k₁ is given by k₁ =
And for B the rate constant k₂ is given by k₂ =
k₁ = A×2.225×10⁻¹⁷
k₂ = A×9.850×10⁻¹⁴
As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times