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Lena [83]
3 years ago
9

Suppose you are asked to find 91,321,972×0.007004. Doing a quick estimate by rounding the numbers in scientific notation, what v

alue would you expect the answer to be close to? (If you need a review of the estimation technique, watch the video Scientific Notation, Part 4.)
63×10^4

Correct
Notice that the expression rounds to (9×10^7)×(7×10^−3)=
63×10^7+(−3)=63×10^4
Physics
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

Product, P=9.1321972\times 10^7\times 7.004\times 10^{-3}

P = 639619.091888

Explanation:

In this case, we need to find the product of two numbers. These are as follows :

N_1=91321972=9.13\times 10^7

N_2=0.007004=7.004\times 10^{-3}

On doing calculation, we get the product of two numbers as :

P=N_1\times N_2

P=9.1321972\times 10^7\times 7.004\times 10^{-3}

P = 639619.091888

In scientific notation the product of two number is given by :

P=63\times 10^4

Hence, this is the required solution.

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Which ratio is greater than 5/8 <br><br> A)12/24 <br><br> B)3/4 <br><br> C)15/24 <br><br> D)4/12
pav-90 [236]

12/24=4x3/8x3

=4/8

4/8 is not correct ans it is less than 5/8

B) 3/4

multiply and divide it by 2 so the denominator should be equal to 8

3x2/4x2=6/8

6/8 is greater that 5/8 hence b is correct option

C)15/24=5/8 which is equalt to 5/8 hence it is not correct answer

D)4/12=1/3 it is also less than 5/8


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3 years ago
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A car of mass m = 1030 kg is traveling down a θ = 13-degree incline. When the car's speed is v0 = 14 m/s, a mechanical failure c
topjm [15]

Answer:

a. F_f = \mu mg cos\theta

b. h = Lsinθ

c. 22.78 m

Explanation:

a. The kinetic friction is the product of kinetic coefficient and normal force N, which is the gravity force in the direction normal to the incline

F_f = \mu N = \mu mg cos\theta

b. As the car travels a distance L down the incline of θ degrees, vertically speaking it would have traveled a distance of:

h = Lsinθ

As we can treat L and h in a right triangle where L is the hypotenuse and h is a side length in opposite of incline angle θ

c. Let g = 9.81 m/s2. the acceleration caused by kinetic friction according to Newton's 2nd law is

a = F_f/m = \mu g cos\theta = 0.45*9.81*cos13^o = 4.3 m/s^2

We can use the following equation of motion to find out the distance traveled by the car:

v^2 - v_0^2 = 2a\Delta s

where v = 0 m/s is the final velocity of the car when it stops, v_0 = 14m/s is the initial velocity of the car when it starts braking, a = -4.3 m/s2 is the deceleration of the car, and \Delta s is the distance traveled, which we care looking for:

0^2 - 14^2 = 2(-4.3)\Delta s

\Delta s = 14^2 / (2*4.3) = 22.78 m

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