Answer:
When there is an increase in the frequency of sound waves, the wavelength decreases.
Explanation:
Given data,
The frequency of the whale changes from 200 Hz to 300 Hz
The formula for frequency and wavelength is,
λ = v/f
Where v is the velocity of the sound waves in water (1531 m/s)
The wavelength at 200 Hz is,
λ = 1531/200
= 7.655 m
The wavelength at 300 Hz is,
λ = 1531/300
= 5.1 m
Hence, when there is an increase in the frequency of sound waves, the wavelength decreases.
The velocity of sound in at 300C is 511.3 m/s.
Explanation:
The equation that gives the speed of sound in ar as a function of the air temperature is the following:
where
T is the temperature of the air, measured in Celsius degrees
In this problem, we want to find the speed of sound in ar for a temperature of
Substituting into the equation, we find:
So, the velocity of sound in at 300C is 511.3 m/s.
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Answer:
The horizontal speed with which the slingshot hits the balloon is approximately 57.358 m/s
Explanation:
The given parameters of the slingshot motion are;
The initial velocity of the slingshot, v = 100 m/s
The angle (to the horizontal) at which the slingshot is fired makes, θ = 55°
The path of the slingshot which hits the stationary balloon at the top of its flight = Parabolic trajectory
The horizontal component of the velocity = vₓ = v·cos(θ) = Constant
vₓ = 100 × cos(55°) ≈ 57.358
The horizontal speed with which the slingshot hits the balloon = vₓ ≈ 57.358 m/s.
Temperature and elevation, if it is cold in Idaho and warm on the eastern end of a mountain side in california (or if warm air is going in that direction) then the cold air, being more dense, will go towards california while the cold air in Idaho will become warm. Same goes for the rest of the world
The study of motion is called kinematics.
