Answer:
3.1°C
Explanation:
Using freezing point depression expression:
ΔT = Kf×m×i
<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>
Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:
9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m
Replacing in freezing point depression formula:
ΔT = 5.12°cm⁻¹×0.472m×1
ΔT = 2.4°C
As freezing point of benzene is 5.5°C, the new freezing point of the solution is:
5.5°C - 2.4°C =
<h3>3.1°C</h3>
<em />
Density always tells you the mass of exactly one unit of volume of a given substance.The answer is 68 g
Answer:through the conduction from magma to water and rocks
Explanation:
I'm assuming you meant 10^(14) instead of 1014
if so, then the energy of one photon will be be 4.76×10^(-19) Joules
At STP, pure ethanol has density 0.789g/mL. 25 mL will have mass 25 (mL) * 0.789 (g/mL)=19.725 g. Round this to 19.7g for three significant figures.
(not fully sure if this is correct)
