Answer:
Explanation:
Given that:
Pressure = 791 mmHg
Temperature = 20.0°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (20 + 273.15) K = 293.15 K
T = 293.15 K
Volume = 100 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 62.3637 L.mmHg/K.mol
Applying the equation as:
791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol × 293.15 K
⇒n of
produced = 0.0493 moles
According to the reaction:-
![CaCO_3 + 2 HCl\rightarrow CaCl_2 + H_2O + CO_2](https://tex.z-dn.net/?f=CaCO_3%20%2B%202%20HCl%5Crightarrow%20CaCl_2%20%2B%20H_2O%20%2B%20CO_2)
1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts
0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts
Moles of calcium carbonate reacted = 0.0493 moles
Molar mass of
= 100.0869 g/mol
The formula for the calculation of moles is shown below:
Thus,
![Mass_{CaCO_3}=4.93\ g](https://tex.z-dn.net/?f=Mass_%7BCaCO_3%7D%3D4.93%5C%20g)
Impure sample mass = 5.28 g
Percent mass is percentage by the mass of the compound present in the sample.
Answer:
The compound which are boh soluble in water and hexane is
B. Ethanol and 1-propanol
Explanation:
The compounds ethanol and 1-propanol are soluble in both hexane and water.
It is soluble in water as both consists of polar end due to hydrogen bonding present in the -OH functional group.
and both are soluble in hexane as they contain a non polar end and the alliphatic hydrocarbon chain in them.
The solubility of alcohols varies in increasing order as the hydrocarbon chain increases. And becaue of this it becomes more non polar.
Non polar properties decreases for branched molecules.
so, the correct option is ethanol and 1-propanol.
The substance is followed by H2O
The present carbon skeleton in an ether is C-C-C-O-C-C-C because ethers conatins C-O-C as functional group