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2 years ago

How many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL

Chemistry

2 answers:

AleksandrR [38]2 years ago

8 0

Answer:

Moles= 1.07mol

Explanation:

C= 8.59M, V= 0.125dm3

n= C×V

n= 8.59×0.125= 1.07mol

Sergio [31]2 years ago

7 0

Answer:

1.07ML

Explanation:

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