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dmitriy555 [2]
3 years ago
8

Hydrogen has a volume of 1.0l and the pressure is 5.4 ATM if the initial temperature is 33 degrees c the final volume is 2.0 l a

nd the final pressure is 4.3 ATM what was the final temperature of the hydrogen?
Chemistry
1 answer:
Andre45 [30]3 years ago
5 0

Answer:

487.33 K.

Explanation:

  • To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant.

T is the temperature of the gas in K.

  • If n is constant, and have two different values of (P, V and T):

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 5.4 atm, V₁ = 1.0 L, T₁ = 33°C + 273 = 306 K.

P₂ = 4.3 atm, V₂ = 2.0 L, T₂ =??? K.

<em>∴ T₂ = P₂V₂T₁/P₁V₁</em> = (4.3 atm)(2.0 L)(306 K)/(5.4 atm)(1.0 L) = <em>487.33 K.</em>

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If 400 Joules of work is done in 20 seconds, how much power was generated?
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Tanya [424]

Answer:

  • <u>0.6826 (68.26%)</u>

Explanation:

<u>1) Find the z-scores:</u>

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  • z = [ 22.6 - 20 ] / 2.6 = 1.00

b) z-score for 17.4 inches length

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<u>2) Probability</u>

Then, you have to find the probability that the length of an infant is between - 1.00 and 1.00 standards deviations (σ) from the mean (μ).

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Explanation:

(a)  As the given chemical reaction equation is as follows.

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(b)  Since, the rate equation is as follows.

                    Rate = K [OCl^{-}][l^{-}]

Let us assume that ([OCl^{-}] = [l^{-}])

Putting the given values into the above equation as follows.

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Therefore, rate when [OCl^{-}] = 1.8 \times 10^{3} M and [I^{-}]= 6.0 \times 10^{4} M is  6.52 \times 10^{5}.

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