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andre [41]
3 years ago
10

A track star runs the first 500 meters of a race in only 75 seconds. What is the track

Physics
2 answers:
irina1246 [14]3 years ago
7 0

Answer:

6.667 m/s

Explanation:

500 meters = 75 seconds

500 meters / 75 seconds = 6.667 m/s

Kobotan [32]3 years ago
3 0
500m/75 sec = 6.6m/sec

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Instead of rolling down the ramp over the step, imagine the ball falls off the back of the ramp directly to the ground. What is
lesya692 [45]

0J

According to the law of conservation of energy, the potential energy is converted to kinetic energy. Remember, potential energy is calculated using height and weight. If the ball is on the ground, height is 0.

8 0
3 years ago
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How can you tell that toast is not warmed up by conduction?
solmaris [256]

Answer:

Toasting in a toaster is usually considered  by (infra red) radiation. But the hot coils touch the toast so an element of heating by conduction occurs as well.

Explanation:

8 0
3 years ago
What types of natural phenomena could serve as time standards?
Delvig [45]

Answer: The rising and setting of the Sun.

The appearance and disappearance of the Moon.

Changes in season.

Appearance and disappearance of the Stars.

Explanation: The rising and setting of the Sun helps can be used as a standard to determine time since the rissing and setting of the Sun occurs at similar time and interval in a given geographical ocation.

The appearance and disappearance of the Moon which occurs during the night and early hours of the morning is similar in a given geographical locationation so it can be used as a standard for Time.

Change in season is another natural phenomenon which occurs at similar times in a given geographical location like Winter/summer, rainy/dry etc can be used as standards for time.

The appearance and disappearance of the Stars can also b used as standards for time in a given geographical location.

5 0
3 years ago
Two particles, one with charge − 7.97 μC −7.97 μC and one with charge 7.75 μC, 7.75 μC, are 8.09 cm 8.09 cm apart. What is the m
mr Goodwill [35]

Answer:

Electric force, F = 84.93 N

Explanation:

Given that,

Charge on particle 1, q_1=-7.97\ \mu C=-7.97\times 10^{-6}\ C

Charge on particle 1, q_2=7.75\ \mu C=7.75\times 10^{-6}\ C

The distance between charges, d = 8.09 cm

To find,

The magnitude of the force that one particle exerts on the other.

Solution,

The electric force of attraction or repulsion is given by the formula as:

F=\dfrac{kq_1q_2}{d^2}

k is the electrostatic constant

F=\dfrac{9\times 10^9\times 7.97\times 10^{-6}\times 7.75\times 10^{-6}}{(8.09\times 10^{-2})^2}

F = 84.93 N

So, the magnitude of the force that one particle exerts on the other is 84.93 N.

4 0
3 years ago
Read 2 more answers
A jet plane flying 600 m/s experience an acceleration of 4.0 g when pulling out of a circular dive. What is the radius of curvat
aksik [14]

Answer:

Option C

Solution:

As per the question:

Velocity of the jet, v = 600 m/s

Acceleration, a = 4.0 g

Now,

To calculate the radius of curvature:

The necessary centripetal force on the jet is given by the force:

F = F_{c}                                               (1)

where

F_{c} = \frac{mv^{2}}{R} = centripetal force

where

m = mass of the jet

R = radius of curvature of the path

Using eqn (1):

ma = \frac{mv^{2}}{R}

Thus

a = \frac{v^{2}}{R}

4.0 g = \frac{600^{2}}{R}

where

g = acceleration due to gravity = 9.8\ m/s^{2}

4.0\times 9.8 = \frac{600^{2}}{R}

R = \frac{600^{2}}{4.0\times 9.8}

R = 9183.67 m ≈ 9200 m

3 0
3 years ago
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