All categories

2 years ago

A track star runs the first 500 meters of a race in only 75 seconds. What is the track

Physics

2 answers:

irina1246 [14]2 years ago

7 0

Answer:

6.667 m/s

Explanation:

500 meters = 75 seconds

500 meters / 75 seconds = 6.667 m/s

Kobotan [32]2 years ago

3 0

500m/75 sec = 6.6m/sec

You might be interested in

A solenoid field is:

Bumek [7]

increased with an increased current flow

7 0

3 years ago

How would a small bar magnet be oriented when placed at position X

Alex Ar [27]

The answer is right here

4 0

2 years ago

Read 2 more answers

In a device like the one shown below, the cylinder is allowed to fall a distance of 300 m. As a result, the temperature of the w

Delvig [45]

Answer:

Increase in the temperature of water would be 0.9 degree C

Explanation:

As we know by energy conservation

Change in the gravitational potential energy of the cylinder = increase in the thermal energy of the water

Here we know that the gravitational potential energy of the cylinder is given as

$U = mgh$

here we have

h = 300 m

now we can say

$Mc\Delta T = (m \times 9.8 \times 300)$

now if the cylinder falls from height h = 100 m

then we have

$Mc\Delta T' = (m \times 9.8 \times 100)$

now from above two equations

$\frac{\Delta T'}{\Delta T} = \frac{100}{300}$

$\Delta T' = 2.7 \times \frac{1}{3} = 0.9 Degree C$

8 0

2 years ago

C is correct just an FYI

belka [17]

Answer:

Huh?

Explanation:

3 0

2 years ago

Reactance Frequency Dependence: Sketch a graph of the frequency dependence of a resistor, capacitor, and inductor. RLC Circuit R

jolli1 [7]

Answer:

$f=\frac{1}{2\pi \sqrt{LC}}$

Explanation:

We know that impedance of a RLC circuit is given by $Z=R+J(X_L-X_C)$

So $Z=\sqrt{R^2+(X_L-X_C)^2}$ here R is resistance $X_L$ is inductive reactance and $X_C$ is capacitive reactance

To minimize the impedance $X_L-X_C$ should be zero we know that $X_L=\omega L\ and \ X_C=\frac{1}{\omega C}$

So $\omega L-\frac{1}{\omega C}=0$

$\omega ^2=\frac{1}{LC}$

$\omega =\sqrt{\frac{1}{LC}}$

We know that $\omega =2\pi f$

So $\omega =2\pi f=\frac{1}{\sqrt{LC}}$

$f=\frac{1}{2\pi \sqrt{LC}}$

Where f is resonance frequency

8 0

2 years ago