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3 years ago

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A ball is shot up from the ground with an initial vertical velocity of 30 m/s. What is the velocity of the ball as it reaches it

s highest point

1 answer:

qaws [65]3 years ago

6 0

Answer:

0 m/s

Explanation:

At the highest point, the vertical velocity is 0 m/s.

There's no horizontal velocity.

So the total velocity at the highest point is 0 m/s.

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A long, thin solenoid has 950 turns per meter and radius 3.00 cm. The current in the solenoid is increasing at a uniform rate of

REY [17]

Answer:

Part a)

$E = 0.188 \times 10^{-3} N/CPart b)[tex]E = 0.376 \times 10^{-3}$ N/C

Explanation:

As we know that the magnetic field near the center of the solenoid is given as

$B = \mu_0 ni$

Also we know by equation of Faraday's law

EMF induced in the closed loop will be equal to rate of change in magnetic flux

so we have

$EMF = A\frac{dB}{dt}$

so we have

$\int E. dL = \pi r^2 (\mu_0 n \frac{di}{dt})$

$E. (2\pi r) = \pi r^2 (\mu_0 n \frac{di}{dt})$

$E = \frac{\mu_0 n r}{2} \frac{di}{dt}$

Part a)

At r = 0.500 cm

we have

$E = \frac{4\pi \times 10^{-7} (950) (0.500 \times 10^{-2})}{2}(63)$

$E = 0.188 \times 10^{-3} N/C$

Part b)

At r = 1.00 cm

we have

$E = \frac{4\pi \times 10^{-7} (950) (1.00 \times 10^{-2})}{2}(63)$

$E = 0.376 \times 10^{-3}$ N/C

5 0

3 years ago

A very long line of charge with charge per unit length +8.00 μC/m is on the x-axis and its midpoint is at x = 0. A second very l

artcher [175]

Answer:

at y=6.29 cm the charge of the two distribution will be equal.

Explanation:

Given:

linear charge density on the x-axis, $\lambda_1=8\times 10^{-6}\ C$

linear charge density of the other charge distribution, $\lambda_2=-6\times 10^{-6}\ C$

Since both the linear charges are parallel and aligned by their centers hence we get the symmetric point along the y-axis where the electric fields will be equal.

Let the neural point be at x meters from the x-axis then the distance of that point from the y-axis will be (0.11-x) meters.

<u>we know, the electric field due to linear charge is given as:</u>

$E=\frac{\lambda}{2\pi.r.\epsilon_0}$

where:

$\lambda=$ linear charge density

r = radial distance from the center of wire

$\epsilon_0=$ permittivity of free space

Therefore,

$E_1=E_2$

$\frac{\lambda_1}{2\pi.x.\epsilon_0}=\frac{\lambda_2}{2\pi.(0.11-x).\epsilon_0}$

$\frac{\lambda_1}{x} =\frac{\lambda_2}{0.11-x}$

$\frac{8\times 10^{-6}}{x} =\frac{6\times 10^{-6}}{0.11-x}$

$x=0.0629\ m$

∴at y=6.29 cm the charge of the two distribution will be equal.

9 0

3 years ago

A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =

Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

$v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2$

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

$v = \omega R\\a = \alpha R$

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

$v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft$

One revolution is equal to the circumference of the drum. So, total number of revolutions is

$x / (2\pi R) = 6/(\pi R)$

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

$a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2$

b) $a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2$

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4 years ago

How do you measure the wavelength of a transverse wave?

DENIUS [597]

By looking at how wiggily the bar is lol

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4 years ago

Some city officials recommend using EZVI because the process treats contaminated water. Consider

Sindrei [870]

Access to Alternative Source of Fuel.

Reduce Surface Toxicity.

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Possible Water Contamination.

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6 0

3 years ago