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2 years ago

13

A ball is shot up from the ground with an initial vertical velocity of 30 m/s. What is the velocity of the ball as it reaches it

s highest point

1 answer:

qaws [65]2 years ago

6 0

Answer:

0 m/s

Explanation:

At the highest point, the vertical velocity is 0 m/s.

There's no horizontal velocity.

So the total velocity at the highest point is 0 m/s.

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a circuit contains 2 ohm and 4 ohm resistors connected in parallel, find the total resistance & the amount of current in eac

Lynna [10]

Answer:

Explanation:

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R = 8 / 6

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2 years ago

The charges that are free to move in a metallic conducting wire and that are responsible for the flow of electric current are

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Answer:Negatively charged particle called Free Electrons

Explanation:

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A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars

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Answer:

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2 years ago

Read 2 more answers

****PLEASE HELP**** THERE ARE TWO QUESTIONS (ITS EASY)

notka56 [123]

but I think it's a and f

and

b and e

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2 years ago

a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br /&

Katen [24]

Answer:

a) T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

sin 30 = $\frac{T_x}{T}$

cos 30 = $\frac{T_y}{T}$

Tₓ = T sin 30

T_y = T cos 30

Y axis

T_y -W = 0

T cos 30 = mg (1)

X axis

Tₓ = m a

they relate it is centripetal

a = v² / r

we substitute

T sin 30 = m $\frac{v^2}{r}$ (2)

a) we substitute in 1

T = $\frac{mg }{cos 30}$

T = $\frac{ 0.2 \ 9.8}{cos \ 30}$

T = 2.26 N

b) from equation 2

v² = $\frac{T \ sin 30 \ r}{m}$

If we know the length of the string

sin 30 = r / L

r = L sin 30

we substitute

v² = $\frac{ T \ sin 30 \ L \ sin 30}{m}$

v² = $\frac{TL \ sin^2 30}{m}$

For the problem let us take L = 1 m

let's calculate

v = $\sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }$

v = 1.68 m / s

8 0

2 years ago