A or C , they both fit but i don’t know the right answer lol
1. Answer;
Natural motion and violent motion
Explanation;
-Natural motion is the motion arising from the nature of an object. This motion does not require an external cause in order to occur. For example: Heavy bodies naturally move toward the center of the earth, therefore falling is a natural motion.
- Natural motion was determined by the nature of the object and how much of the four classical elements it contained. Violent motion is caused by external forces applied to the object.
2. Answer;
Natural motion
Explanation;
Natural motions are those motions that objects naturally did: objects on earth fell towards the center of the earth. Heavenly objects naturally moved in circles. Additionally, heavy bodies naturally move toward the center of the earth, therefore falling is a natural motion. The natural motion of objects is one of the characteristics of an object.
3. Answer;
To assume that Earth and the other planets rotate around the sun
Explanation;
-Copernicus proposed an alternative theory--that the Earth was a planet orbiting the Sun, and that all planets moved in circles, one inside the other. Mercury and Venus had the smallest circles, smaller than that of the Earth, and therefore their position in the sky was always near the Sun's.
-That made it easy to estimate their distances from the Sun in terms of the Earth-Sun distance.
D is the answers Gases from a dead star gather and contract.
Answer:
0.02325 m^3
Explanation:
P1 = 100000Pa , v1 = 0.0279m^3
P2= 120000Pa . V2 = ?
as mass and temperature are constant using ratio method for Boyle'slaw
P2V2= P1V1
or V2= P1V1/P2
V2 = 100000×0.0279/120000
V2= 0.02325 m^3
Answer:
1.696 nm
Explanation:
For a diffraction grating, dsinθ = mλ where d = number of lines per metre of grating = 5510 lines per cm = 551000 lines per metre and λ = wavelength of light = 467 nm = 467 × 10⁻⁹ m. For a principal maximum, m = 1. So,
dsinθ = mλ = (1)λ = λ
dsinθ = λ
sinθ = λ/d.
Also tanθ = w/D where w = distance of center of screen to principal maximum and D = distance of grating to screen = 1.03 m
From trig ratios 1 + cot²θ = cosec²θ
1 + (1/tan²θ) = 1/(sin²θ)
substituting the values of sinθ and tanθ we have
1 + (D/w)² = (d/λ)²
(D/w)² = (d/λ)² - 1
(w/D)² = 1/[(d/λ)² - 1]
(w/D) = 1/√[(d/λ)² - 1]
w = D/√[(d/λ)² - 1] = 1.03 m/√[(551000/467 × 10⁻⁹ )² - 1] = 1.03 m/√[(1179.87 × 10⁹ )² - 1] = 1.03 m/1179.87 × 10⁹ = 0.000848 × 10⁻⁹ = 0.848 × 10⁻¹² m = 0.848 nm.
w is also the distance from the center to the other principal maximum on the other side.
So for both principal maxima to be on the screen, its minimum width must be 2w = 2 × 0.848 nm = 1.696 nm
So, the minimum width of the screen must be 1.696 nm