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ikadub [295]
3 years ago
13

A ball is shot up from the ground with an initial vertical velocity of 30 m/s. What is the velocity of the ball as it reaches it

s highest point
Physics
1 answer:
qaws [65]3 years ago
6 0

Answer:

0 m/s

Explanation:

At the highest point, the vertical velocity is 0 m/s.

There's no horizontal velocity.

So the total velocity at the highest point is 0 m/s.

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Two ice skaters stand together. They push off and travel directly away from each other, the boy with a velocity of v = +0.35 m/s
DIA [1.3K]

Answer:

-0.55m/s

Explanation:

Given that: For the boy

Weight = 745N

Velocity = +0.35 m/s

Mass of the boy = ?

g = 9.81m/s^2

W = mg

745 = m×9.81

m = 75.94kg

For the girl

Given that:

Weight = 477 N

g = 9.81m/s^2

m = ?

W = mg

477 = m×9.81m/s^2

m = 48.62kg

To solve for the v of the girl, the two has to add up

48.62kg×v + 75.94kg×+0.35 m/s = 0

48.62v + 26.579 = 0

48.62v = - 26.579

v = -26.579/48.62

v = -0.5466

v = -0.55m/s

Hence, the velocity of the girl is -0.55m/s.

The negative sign is as a result of the two of them moving is opposite direction.

5 0
3 years ago
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. What is the vertical compon
elixir [45]

Answer:

<h3>473.8 m/s; 473.8 m/s</h3>

Explanation:

Given the initial velocity U = 670m/s

Horizontal velocity Ux = Ucos theta

Vertical component of the cannon velocity Uy = Usin theta

Given

U = 670m/s

theta = 45°

horizontal component of the cannonball’s velocity = 670 cos 45

horizontal component of the cannonball’s velocity = 670(0.7071)

horizontal component of the cannonball’s velocity = 473.757m/s

Vertical component of the cannonball’s velocity = 670 sin 45

Vertical component of the cannonball’s velocity  = 670 (0.7071)

Vertical component of the cannonball’s velocity  = 473.757m/s

Hence pair of answer is 473.8 m/s; 473.8 m/s

6 0
3 years ago
When visiting some countries, you may see a person balancing a load on the head. Explain why the center of mass of the load need
Vinvika [58]

Explanation:

If the center of the load is directly above the vertebrae, there is no torque in the system. This is a good thing so that the vertebrae are not put out of alignment over time. (Of course, this still doesn't prevent compression of the vertebrae over time, which is a possibility.)

3 0
3 years ago
ANSWER ASAP
Hoochie [10]
The answer to this would inFact be A
6 0
3 years ago
Un objeto de 1400 g de masa se mueve bajo la acción de una fuerza constante con una aceleración de 0,5 m/s2 , sobre una superfic
igomit [66]

Answer:

if you spoke this in english i can help you out

Explanation:

3 0
3 years ago
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