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2 years ago

Which of the following shows resistors in a parallel circuit

Physics

2 answers:

Alexeev081 [22]2 years ago

7 0

The bottom drawing do

liubo4ka [24]2 years ago

5 0

Answer:

Circuit (b)

Explanation:

In parallel combination of resistors, the current flowing in each branch divides while the potential difference remains the same in entire circuit. The equivalent resistance is given by the following formula as :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}$

While in series combination, the current remains the same while the volatge across each resistor is different. Their equivalent is given by:

$R_{eq}=R_1+R_2+R_3$

In the given figure, circuit (b) shows parallel combination of resistors. Also, the resistors are connected in two different paths in circuit (b).

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Makovka662 [10]

Answer:

3.42N

Explanation:

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Use the equation: F = (GMm)/(r^2)

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m = mass2 (1kg)

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3 years ago

On a Saturday afternoon, you decide to pay a neighborhood kid to mow your lawn. The kid usesa manual push lawn mower with a mass

Mars2501 [29]

Answer with Explanation:

We are given that

A.Mass,m=12 kg

$\theta=53^{\circ}$

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Speed,v=1.5m/s

Net force in x direction must be zero

$F_{net}=0$

$Fsin\theta-f=0$

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Net force in y direction

$N-mg-Fcos\theta=0$

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$f=\mu_kN=\mu_k(mg+Fcos\theta)$

$Fsin\theta=\mu_k(mg+Fcos\theta)$

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$Fsin\theta-\mu_kFcos\theta=\mu_kmg$

$F(sin\theta-\mu_kcos\theta)=\mu_kmg$

$F=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}$

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$P=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}v$

Where $g=9.8m/s^2$

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$P=\frac{0.16\times 12\times 9.8}{sin53-0.16cos53}\times 1.5$

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3 years ago

A wave passes along the surface of the water in a ripple tank. Describe the motion of a molecule on the surface as the water pas

laila [671]

Answer:

Explanation:

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2 years ago

What is the volume of 45.6 g of silver if the density of silver is 10.5 g/ml?

Leviafan [203]

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2 years ago

Read 2 more answers

A positively charged sphere with a charge of 8Q is separated from a negatively charged sphere -2Q by a distance r. There is an a

djverab [1.8K]

Answer:

Explanation:

For the first case , the expression for electrostatic force can be given by the following .

F = K x 8Q x 2Q / r² where k is a constant .

F = K 16 Q² / r²

When they touch , some charge is neutralized . Net charge remaining

= 8Q - 2 Q = 6 Q

Charge on each sphere = 6Q/2 = 3 Q .

Force between them

F₁ = k 3Q x 3 Q / r² = k 9 Q² / r²

F₁ / F = 9 / 16

F₁ = 9 F / 16 .

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2 years ago