The distance of the image formed is 44.27 cm and the magnification of the image is 0.7.
<h3>Location of the image</h3>
The image distance formed by the lens is calculated as follows;
1/v + 1/u = -1/f
where;
- v is the image distance
- u is the object distance
- f is the focal length of the lens
1/v = -1/f - 1/u
1/v = -(-1/26) - 1/63
1/v = 1/26 - 1/63
1/v = 0.022588
v = 1/0.022588
v = 44.27 cm
<h3>What is magnification of lens?</h3>
The magnification of a lens is defined as the ratio of the height of an image to the height of an object.
<h3>Magnification of the image formed</h3>
The magnification of the image is calculated as follows;
Magnification = image distance/object distance
M = 44.27/63
M = 0.7
Thus, the distance of the image formed is 44.27 cm and the magnification of the image is 0.7.
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C. white light
Explanation:
All the visible color light waves are seen together and makes up a white light.
Visible light is made up of different colors and when they join together they are seen as the white light around us.
- During rainbow formation, we see the different colors of light that makes up a white light.
- when white light passes through a glass prism, the velocity and wavelength changes and we can see the different components of light.
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electromagnetic waves brainly.com/question/12450147
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The final velocity is 5.87 m/s
<u>Explanation:</u>
Given-
mass, = 72 kg
speed, = 5.8 m/s
, = 45 kg
, = 12 m/s
Θ = 60°
Final velocity, v = ?
Applying the conservation of momentum:
X + X = ( + ) v
72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v
v = 417.6 + 540 X
v = 417.6 +
v = 5.87 m/s
The final velocity is 5.87 m/s
Answer:
Explanation:
Given
Electron is accelerated 3.5 kV potential difference
Distance between plates d=29 mm
The potential difference between plates is V=100 V
here, the kinetic energy of an electron is acquired through a potential difference of 3.5 kV
To move in a straight line Force due to magnetic field must be balanced by force due to charge
Answer:
4. deducing and applying natural laws