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igor_vitrenko [27]

2 years ago

6

How much work is the adult completing 1.6j 0.6j 20j 1,500j I NEED THIS DONE FAST

1 answer:

koban [17]2 years ago

6 0

Answer:

20j

Explanation:

espero haverte

ayudado

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The work of brain mind interface is to

Genrish500 [490]

The work of Brian mind interface is to learn that’s my guess lol

4 0

3 years ago

Eugene describes the physical property of a material as “sweet and floral.” What physical property of the material is Eugene mos

shusha [124]

The correct answer would be odor. Because it's sweet. Boiling shape and hardness have nothing to do with sweet and floral :)

7 0

3 years ago

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How to tell if a circuit is connected in.a series.or parallel?

stepladder [879]

Series circuits split the voltage of resistors, so if you see several diodes connected <em>in series </em>or all next to each other, just a complete loop, it will be in series.

Parallel circuits split the current of resistors, so if you see several diodes connected along different branches or pathways, it will be in parallel.

7 0

3 years ago

A nautical mile is 6076 feet, and 1 knot is a unit of speed equal to 1 nautical mile/hour. How fast is a boat going 8 knots goin

mezya [45]

Answer:

The speed of the boat is equal to 13.50 ft/s.

Explanation:

given,

1 nautical mile = 6076 ft

1 knot = 1 nautical mile /hour

1 knot = 6076 ft/hr

speed of boat = 8 knots

8 knots = 8 nautical mile /hour

= $8 \times \dfrac{6076\ ft}{1\nautical\ mile}\times \dfrac{1\ hour}{60\times 60\ s}$

= 13.50 ft/s

The speed of the boat is equal to 13.50 ft/s.

5 0

3 years ago

The classic Millikan oil-drop experiment was the first to obtain an accurate measurement of the charge on an electron. In it, oi

Sati [7]

Answer:

$1.56\times 10^5 N/C$

Explanation:

The electric field that will balance the weight of the oil drop can be calculated using the following:

electric force, F = e E ( where, e is the charge of an electron and E is the electric field)

weight, W = 2.5 ×10⁻¹⁴ N

e E = W

$E =\frac{W}{e}$

Substitute the values:

$E =\frac{ 2.5 \times 10^{-14} N}{1.6\times10^{-19}C}= 1.56\times 10^5 N/C$

6 0

3 years ago

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