The distance of the image formed is 44.27 cm and the magnification of the image is 0.7.
<h3>Location of the image</h3>
The image distance formed by the lens is calculated as follows;
1/v + 1/u = -1/f
where;
- v is the image distance
- u is the object distance
- f is the focal length of the lens
1/v = -1/f - 1/u
1/v = -(-1/26) - 1/63
1/v = 1/26 - 1/63
1/v = 0.022588
v = 1/0.022588
v = 44.27 cm
<h3>What is magnification of lens?</h3>
The magnification of a lens is defined as the ratio of the height of an image to the height of an object.
<h3>Magnification of the image formed</h3>
The magnification of the image is calculated as follows;
Magnification = image distance/object distance
M = 44.27/63
M = 0.7
Thus, the distance of the image formed is 44.27 cm and the magnification of the image is 0.7.
Learn more about magnification here: brainly.com/question/1599771
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