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Drupady [299]
2 years ago
10

The electric field force is a ___________ quantity.

Physics
1 answer:
Rufina [12.5K]2 years ago
4 0

Answer:

Explanation:

The force due to an electric field is a vector quantity because it has direction and magnitude just like Newton's Law

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An ac generator with peak voltage 100 volts is placed across a 10-? resistor. What is the average power dissipated?
Romashka [77]
The correct answer is: Average Power  = 500 W

Explanation:
Root-mean square voltage = Vrms = Vpeak /√2 = 100 / √2 volts
Resistance = R = 10 Ω
Average power = Pavg = (Vrms)^2<span> / R </span>= (100 * 100) / (2 * 10) = <span>500 W</span>
3 0
3 years ago
You are 1.8 m tall and stand 2.8 m from a plane mirror that extends vertically upward from the floor. on the floor 1 m in front
velikii [3]
This problem must be solved using a sketch. I attached an illustration of the problem.
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Now we can write tangens equations:
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We solve for h:
\frac{h-0.8}{1}=\frac{1.8-h}{2.8}\\&#10;2.8h-0.8\cdot 2.8=1.8-h\\&#10;3.8h=1.8+2.24\\&#10;h=\frac{4.04}{3.8}\\&#10;h=1.06m


6 0
3 years ago
Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
DiKsa [7]

Answer:

a.\rm -1.49\ m/s^2.

b. \rm 50.49\ m.

Explanation:

<u>Given:</u>

  • Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).

At time t = 3 seconds,

\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.

For the time interval of 2 seconds,

\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.

It is the displacement of the particle in 2 seconds.

7 0
3 years ago
Muscular Endurance is the ability of a muscle to continue to perform without fatigue.
Art [367]

Answer:

True.

Explanation:

Defenintion of Muscular Endurance:  

The ability of a muscle (or set of muscles) to perform a repeated action without tiring.

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3 years ago
Three oxygen isotopes
igomit [66]
Stable isotopes, radioisotopes, oxygen

6 0
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