Complete Question
An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters ) is the airplane above the ground 13 seconds after takeoff?
Answer:
The height is 
Explanation:
From the question we are told that
The speed at which the plane takes off is 
The angle at which it takes off is 
The time taken is 
The vertical distance traveled is mathematically represented as
Substituting values
It is -59 i think or just ask someone esle for help
Here's the rule you need to know
in order to answer this question:
1 full circle ==> 360 degrees .
Got that ?
Now you could set up a proportion:
(30 degrees) / (0.01 second) = (360 degrees) / (time for full period)
Cross-multiply the proportion:
(30°) · (period) = (360°) · (0.01 sec)
Divide each side by (30°) : Period = (360° · 0.01 sec) / (30°)
= (3.6° · sec) / (30°)
= (3.6 / 30) sec
= 0.12 sec .
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Another way to look at it:
30° takes 0.01 second
60° takes 0.02 second
90° takes 0.03 second
120° takes 0.04 second
150° takes 0.05 second
180° takes 0.06 second
210° takes 0.07 second
240° takes 0.08 second
270° takes 0.09 second
300° takes 0.10 second
330° takes 0.11 second
360° takes 0.12 second
