An airplane takes off a runway at a constant speed of 49m/s at constant angle 30 to the horizontal
1 answer:
Complete Question
An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters ) is the airplane above the ground 13 seconds after takeoff?
Answer:
The height is
Explanation:
From the question we are told that
The speed at which the plane takes off is
The angle at which it takes off is
The time taken is
The vertical distance traveled is mathematically represented as
Substituting values
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Answer:3
Explanation:
First ball is thrown with horizontal velocity while other ball is dropped from cliff such that both have zero vertical velocity. So both balls have to cover a distance equal to the height of cliff with same initial velocity.
time taken is given by
where h=height of cliff
g=acceleration due to gravity
horizontal velocity to first ball will make the ball to travel more horizontal distance as compared to second ball.
Option 3 is correct
Answer:
Magnitude of induced emf is 0.00635 V
Explanation:
Radius of circular loop r = 45 mm = 0.045 m
Area of circular loop
Magnetic field is increases from 250 mT to 350 mT
Therefore change in magnetic field
Emf induced is given by
Magnitude of induced emf is equal to 0.00635 V