Question

An airplane takes off a runway at a constant speed of 49m/s at constant angle 30 to the horizontal

Answer 1

Complete Question

An airplane takes off a runway at a constant speed of 49 m/s at constant angle 30 to the horizontal.How high (in meters )  is the airplane above the ground 13 seconds after takeoff?

Answer:

The height  is $H = 318.5 \ m$

Explanation:

From the question we are told that

   The speed at which the plane takes off is  $u = 49 \ m/s$

      The angle at which it takes off is  $\theta = 30 ^o$

        The time taken is $t = 13 s$

The vertical distance traveled is  mathematically represented as

          $H = u sin \theta t$

Substituting values  

         $H = (49) * sin (30) *13$

        $H = 318.5 \ m$