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Svetlanka [38]
3 years ago
15

What is the necessary conditions for the production of sound?

Physics
1 answer:
TEA [102]3 years ago
8 0

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: Something that's vibrating, and you also need medium for those vibrations to start in.

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

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Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne
VLD [36.1K]

Answer:

The the maximum emf is 2.52\times10^{-11}\ V

Explanation:

Given that,

Magnetic field B = 1.40\times10^{-3}\ T

Frequency = 60 Hz

Diameter = 7.8 μm

We need to calculate the maximum emf

Using formula of emf

\epsilon=NBA\omega

Where, N = number of turns

B= magnetic field

A = area

Put the value in to the formula

\epsilon=1\times1.40\times10^{-3}\times\pi\times(\dfrac{7.8\times10^{-6}}{2})^2\times2\times\pi\times60

\epsilon=2.52\times10^{-11}\ V

Hence, The the maximum emf is 2.52\times10^{-11}\ V

5 0
3 years ago
How do you find the range of a data set
GaryK [48]
Range is only the highest value subtracted from the lowest value unless of your talking about line plots
4 0
4 years ago
For the following equation answer the following:
sergij07 [2.7K]

Answer:

4Al + 3O2 + heat ------> 2Al2O3

Explanation:

It is endothermic reaction.

8 0
3 years ago
A Coolie raises a box of mass 20 kg to a height of 1.5m. If the force of gravity on 1 kg is 10N. The work done by the Coolie is​
Makovka662 [10]
Solution:
Mass(m)=20kg
Displacement (s)=1.5m
For 1 kg force of gravity=10N
We have,
F=mg
or,10=1xg
or g=10m/s^2
Then,
Total work done by the coolie(W)=force x displacement
or,W=mxgxs
=20x10x1.5
=300J
5 0
3 years ago
In a radio, frequency modulation refers to encoding a wave with information by:
balandron [24]

In radio communication, "frequency modulation" refers to encoding a wave with information by adjusting how many waves are produced per second.<em> (b) </em>That's the "frequency" of the radio carrier signal.

6 0
3 years ago
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