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sesenic [268]
3 years ago
9

Which statement is best supported by the information in the chart? Wave X and Wave Y are mechanical waves, and Wave Z is an elec

tromagnetic wave. Wave X and Wave Y are electromagnetic waves, and Wave Z is a mechanical wave. Wave X and Wave Z are electromagnetic waves, and Wave Y is a mechanical wave. Wave X and Wave Z are mechanical waves, and Wave Y is an electromagnetic wave.
Physics
1 answer:
cluponka [151]3 years ago
5 0

Answer:

what??????????????????????

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b) Assume the rod is 0.60 m long and has a mass of 0.50 kg, and the clay blob has a mass of 0.20 kg and moves at an initial velo
SOVA2 [1]

Answer:

The correct answer is "6.96 rad/s".

Explanation:

The given values are:

Length,

L = 0.6 m

Mass,

m₁ = 0.5 kg

m₂ = 0.2 kg

Initial velocity,

V = 8 m/s

Now,

The final angular velocity will be:

⇒ \omega =\frac{6m_1V}{(4m_1+3m_2)L}

By substituting the values, we get

⇒     =\frac{6\times 0.2\times 8}{(4\times 0.2+3\times 0.5)0.6}

⇒     =\frac{9.6}{1.38}

⇒     =6.96 \ rad/s

4 0
3 years ago
Select the correct answer.
arsen [322]

Answer:

C

Explanation:

Force is a vector quantity. So, it has magnitude and direction which can also be describe as strength and direction

5 0
3 years ago
Read 2 more answers
Steam is to be condensed on the shell side of a heat exchanger at 150 oF. Cooling water enters the tubes at 60 oF at a rate of 4
zalisa [80]

Answer:

a. 572Btu/s

b.0.1483Btu/s.R

Explanation:

a.Assume a steady state operation, KE and PE are both neglected and fluids properties are constant.

From table A-3E, the specific heat of water is c_p=1.0\ Btu/lbm.F, and the steam properties as, A-4E:

h_{fg}=1007.8Btu/lbm, s_{fg}=1.6529Btu/lbm.R

Using the energy balance for the system:

\dot E_{in}-\dot E_{out}=\bigtriangleup \dot E_{sys}=0\\\\\dot E_{in}=\dot E_{out}\\\\\dot Q_{in}+\dot m_{cw}h_1=\dot m_{cw}h_2\\\\\dot Q_{in}=\dot m_{cw}c_p(T_{out}-T_{in})\\\\\dot Q_{in}=44\times 1.0\times (73-60)=572\ Btu/s

Hence, the rate of heat transfer in the heat exchanger is 572Btu/s

b. Heat gained by the water is equal to the heat lost by the condensing steam.

-The rate of steam condensation is expressed as:

\dot m_{steam}=\frac{\dot Q}{h_{fg}}\\\\\dot m_{steam}=\frac{572}{1007.8}=0.5676lbm/s

Entropy generation in the heat exchanger could be defined using the entropy balance on the system:

\dot S_{in}-\dot S_{out}+\dot S_{gen}=\bigtriangleup \dot S_{sys}\\\\\dot m_1s_1+\dot m_3s_3-\dot m_2s_2-\dot m_4s_4+\dot S_{gen}=0\\\\\dot m_ws_1+\dot m_ss_3-\dot m_ws_2-\dot m_ss_4+\dot S_{gen}=0\\\\\dot S_{gen}=\dot m_w(s_2-s_1)+\dot m_s(s_4-s_3)\\\\\dot S_{gen}=\dot m c_p \ In(\frac{T_2}{T_1})-\dot m_ss_{fg}\\\\\\\dot S_{gen}=4.4\times 1.0\times \ In( {73+460)/(60+460)}-0.5676\times 1.6529\\\\=0.1483\ Btu/s.R

Hence,the rate of entropy generation in the heat exchanger. is 0.1483Btu/s.R

4 0
4 years ago
3. Order the following lengths from shortest to longest.
horrorfan [7]

Answer: d < a < c < b

3.3 cm < 400 mm < 170 m < 22 km

Explanation:

Firstly, let's convert these length to meters m, in order to work with the same units:

a. 400 millimeters

400 mm \frac{1m}{1000 mm}=0.4 m

b. 22 kilometers

22 km \frac{1000m}{1 km}=22000 m

c. 170 meters

Here the lenght is already in meters

d. 3.3 centimeters

3.3 cm \frac{1m}{100 cm}=0.033 m

Now that we have all the lengths in meters, we can order them from shortest to longest:

0.033 m < 0.4 m < 170 m < 22000 m

or

d < a < c < b

7 0
4 years ago
Hi i need help. thNKS
Ede4ka [16]

Answer:

8

Explanation:

Groups go down, periods go across :)

3 0
3 years ago
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