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Marina CMI [18]
3 years ago
15

Will an empty balloon have precisely the same apparent weight on a scale as a balloon filled with air? Explain.

Chemistry
2 answers:
hram777 [196]3 years ago
4 0
The notion <span>an empty balloon have precisely the same apparent weight on a scale as a balloon filled with air depends on the diameter of the balloon. The weight of the balloon  filled with air is equal to the mass of the balloon and the mass of the air inside. The mass of air inside is equal to the density of air multiplied by the volume of the balloon. If the balloon is large, then the two masses are equal whereas if not, the mass of air inside the inflation is neglible</span>
pentagon [3]3 years ago
3 0
<span>They would not, but only for this reason: In the the full balloon, slightly more molecules of air are pressing downwards on the same position. The difference lies in the weight of the volume of the inflated balloon that does not lie in space above the deflated balloon.</span>
An air filled balloon is heavier than the empty one.
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Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of microgra
leonid [27]

Answer:

0.125 mg

Explanation:

<em>The correct answer would be 0.125 mg</em>

<u>According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.</u>

milligram = 10^{-3}

microgram = 10^{-6}

Hence,

1 milligram = 1000 micrograms or 1 microgram = 10^{-3} milligram

Therefore, 125 micrograms will be:

  125/1000 = 0.125 milligram

4 0
3 years ago
In the following reaction, which component acts as an oxidizing agent? 10 I− (aq) + 2 MnO4− (aq) + 16 H+ (aq) → 5 I2 (s) + 2 Mn2
antiseptic1488 [7]

Answer:

The oxidizing agent is the MnO₄⁻

Explanation:

This is the redox reaction:

10 I⁻ (aq) + 2 MnO₄⁻ (aq) + 16 H⁺ (aq) → 5 I₂ (s) + 2 Mn²⁺ (aq) + 8 H2O (l)

Let's determine the oxidation and the reduction.

I⁻ acts with -1 in oxidation state and changes to 0, at I₂.

All elements in ground state has 0 as oxidation state.

As the oxidation state has increased, this is the oxidation, so the iodide is the reducing agent.

In the permanganate (MnO₄⁻), Mn acts with +7 in oxidation state and decreased to Mn²⁺. As the oxidation state is lower, we talk about the reduction. Therefore, the permanganate is the oxidizing agent because it oxidizes iodide to iodine

3 0
3 years ago
I need help with this!!
8_murik_8 [283]

Answer:

0.84kg of gatorade powder is needed.

Explanation:

From the question given above, we were told that the team manager mixes 0.6kg of gatorade powder with 5 gallons of water.

Now, to obtain the desired amount of the powder of gatorade needed for 7 gallons of water, we simply do the following:

If 0.6kg of gatorade powder required 5 gallons of water,

Then Xg of gatorade will require 7 gallons of water i.e

Xg of gatorade = (0.6 x 7)/5

Xg of gatorade = 0.84kg

Therefore, to maintain the same gatorade mixture, the team manager must mix 0.84kg of gatorade powder with the 7 gallons of water.

4 0
3 years ago
Which chemical reaction is the fastest?
pychu [463]

Answer:

C) drain cleaner fizzes up as it encounters blockages in a pipe

Explanation:

4 0
3 years ago
To begin the experiment, a bomb calorimeter is filled with 1.11 g CH4 and an excess of oxygen. The heat capacity of the calorime
Flura [38]
There are several information's already given in the question. Based on those information's the answer can be easily determined.

M = <span>1.11 g CH4
C = </span>4.319 kJ g C⋅°
∆T = 35.65 - 24.85 degree centigrade
     = 10.8 degree centigrade.
Then
∆H =−M ⋅ C ⋅∆T
      = - 1.11 * 4.319 * 10.8
      = - 51.776 kJ/<span>mol

I hope the procedure is clear enough for you to understand.</span>
6 0
3 years ago
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