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Aleonysh [2.5K]
3 years ago
14

PLEASE PLEASE PLEASE PLEASE HELP CHOOSE TWO DONT GUEES PLEASE ITS MY ONLY HOPE.

Chemistry
2 answers:
hichkok12 [17]3 years ago
7 0
I think it's A and B! I haven't done the rock cycle in forever but c has nothing to do with rocks and i don't think it's d! Hopefully this helps!
balu736 [363]3 years ago
6 0
A I don’t know how to explain it but I just know that it’s A
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Nonferrous alloys do not contain<br> a. copper.<br> b. brass.<br> c. gold.<br> d. iron.
marin [14]
Nonferrous alloys do not contain iron as the name suggests. Ferrous is the latin word for iron. These alloys use precious metals such as gold, silver, platinum and other metals like copper, aluminum, lead, zinc and even alloys like brass. Answer is D.
6 0
3 years ago
A sample of an ionic compound that is often used as a dough conditioner is analyzed and found to contain 4.628 g of potassium, 9
Roman55 [17]

Answer:

The empirical formula of the compound is = KBrO_3

The name of the compound is potassium bromate.

Explanation:

Mass of potassium = 4.628 g

Moles of potassium = \frac{4.628 g}{39 g/mol}=0.1187 mol

Mass of bromine = 9.457 g

Moles of bromine = \frac{9.457 g}{80 g/mol}=0.1182 mol

Mass of oxygen = 5.681 g

Moles of oxygen = \frac{5.681 g}{16 g/mol}0.3551

For empirical formula of the compound, divide the least number of moles from all the moles of elements present in the compound:

Potassium :

\frac{0.1187 mol}{0.1182 mol}=1.0

Bromine;

\frac{0.1182 mol}{0.1182 mol}=1.0

Oxygen ;

\frac{0.3551 mol}{0.1182 mol}=3.0

The empirical formula of the compound is = KBrO_3

The name of the compound is potassium bromate.

5 0
3 years ago
What are the tiny green structures that plants use to make their own food?
Minchanka [31]
I think it’s lysosomes
4 0
3 years ago
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Use your periodic table of elements. Take any element from the second column, except for beryllium and calcium, and answer the f
Alja [10]

Answer:

Radium (Ra)

Metal

Alkaline Earth Metal

Protons & Electrons: 88

Neutrons: 138

Explanation:

6 0
2 years ago
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What mass of CO is needed to react completely with55.0 g of Fe2O3(s)+CO(g) yield Fe(s)+CO2(g)?
Katarina [22]

Answer:

28.9 g

Explanation:

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Gather all the information in one place</em> with molar masses above the formulas and masses below them.  

M_{r}:     159.69    28.01

              Fe₂O₃ + 3CO ⟶ 2Fe + 3CO₂

Mass/g:  55.0

1. Use the molar mass of Fe₂O₃ to calculate the moles of Fe₂O₃.

\text{Moles of Fe$_{2}$O$_{3}$} =\text{55.0 g Fe$_{2}$O$_{3}$} \times \frac{\text{1 mol Fe$_{2}$O$_{3}$}}{\text{159.69 g Fe$_{2}$O$_{3}$}}= \text{0.3444 mol Fe$_{2}$O$_{3}$}

2. Use the molar ratio of CO:Fe₂O₃ to calculate the moles of CO.

\text{Moles of CO} = \text{0.3444 mol Fe$_{2}$O$_{3}$} \times \frac{\text{3 mol CO}}{\text{1 mol Fe$_{2}$O$_{3}$}}= \text{1.033 mol CO}

3.Use the molar mass of CO to calculate the mass of CO.

\text{Mass of CO} = \text{1.033 mol CO}  \times \frac{\text{28.01 g CO} }{\text{1 mol CO}}= \textbf{28.9 g CO}  

3 0
3 years ago
Read 2 more answers
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