1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Viefleur [7K]
3 years ago
5

PLEASE ANSWER FAST AND YOU WILL GET 15 POINTS AND BRAINLIEST if you answer both questions

Chemistry
1 answer:
nika2105 [10]3 years ago
8 0

Answer:

1. C. Lithosphere

2. A. Earthquakes

You might be interested in
Acetylene reacts with oxygen to form carbon dioxide and water according to the following unbalanced reaction:
Lelechka [254]

Answer:

Mass of excess reactant leftover after reaction is complete = 34.2 g \mathrm{C}_{2} \mathrm{H}_{2}.

Explanation:

Acetylene reacts with oxygen to form carbon dioxide and water, equation given is unbalanced

\mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})

Firstly equation is balanced:

2 \mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{g})+5 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 4 \mathrm{CO}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})

\text { Moles of } \mathrm{CO}_{2} \text { from } \mathrm{C}_{2} \mathrm{H}_{2}

\text { Molar mass of } \mathrm{C}_{2} \mathrm{H}_{2} \text { is } 26.04 \mathrm{g} / \mathrm{mol}

\text { Moles of } \mathrm{C}_{2} \mathrm{H}_{2}=38.7 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2} \times \frac{1 \mathrm{mol} c_{2} \mathrm{H}_{2}}{26.04 \mathrm{gm} \mathrm{c}_{2} \mathrm{H}_{2}}=1.48 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2}

1.48 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2} \times \frac{4 \mathrm{mol} \mathrm{Co}_{2}}{2 \mathrm{mol} C_{2} \mathrm{H}_{2}}=2.96 \mathrm{mol} \mathrm{CO}_{2}

\text { Moles of } \mathrm{CO}_{2} \text { from } \mathrm{O}_{2}:

\text { Molar mass of } \mathrm{O}_{2} \text { is } 32.00 \mathrm{g} / \mathrm{mol}

\text { Moles of } \mathrm{O}_{2}=13.7 \mathrm{gm} \mathrm{O}_{2} \times \frac{1 \mathrm{mol} O_{2}}{32.00 \mathrm{gm} 0_{2}}=0.428 \mathrm{mol} \mathrm{O}_{2}

\text { Here we come to know that } 4 \mathrm{mol} \mathrm{CO}_{2} \equiv 5 \mathrm{mol} \mathrm{O}_{2}, \text { hence }

0.428 \mathrm{mol} \mathrm{O}_{2} \times \frac{4 \mathrm{mol} \mathrm{co}_{2}}{5 \mathrm{mol} O_{3}}\left(4 \mathrm{mol} \mathrm{CO}_{2}\right) /\left(5 \mathrm{mol} \mathrm{O}_{2}\right)=0.3424 \mathrm{mol} \mathrm{CO}_{2}

Here we come to know O2 is limiting reactant as it gives smaller amount of \mathrm{CO}_{2} So \mathrm{C}_{2} \mathrm{H}_{2} is excess reactant.

Mass of excess reactant utilized:

0.428 \mathrm{mol} \mathrm{O}_{2} \times \frac{2 \mathrm{mol} C_{2} \mathrm{H}_{2}}{5 \mathrm{mol} O_{2}}=0.1712 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2}

0.1712 \mathrm{mol} \mathrm{C}_{2} \mathrm{H}_{2} \times \frac{26.04 \mathrm{gm} \mathrm{c}_{2} \mathrm{H}_{2}}{1 \mathrm{mol} C_{2} \mathrm{H}_{2}}=4.45 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}

Mass of excess reactant leftover after reaction is complete:

38.7 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}-4.45 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}=34.2 \mathrm{gm} \mathrm{C}_{2} \mathrm{H}_{2}.

7 0
3 years ago
What is the formula for calculating the energy of a photon?
iren2701 [21]

E=hf is the answer gotta run now hope the best for yall

5 0
3 years ago
What contribution did Robert Boyle make towards the field of chemistry
GREYUIT [131]

Answer:

Boyle's law, which describes the inversely proportional relationship between the absolute pressure and volume of a gas, if the temperature is kept constant within a closed system. Among his works, The Sceptical Chymist is seen as a cornerstone book in the field of chemistry.

8 0
3 years ago
Use the drop-down menus to select the names of the labeled structures.<br><br> A: B: C:
Naya [18.7K]

Answer:

A Petal B Stigma C Stamen

Explanation:

5 0
3 years ago
Read 3 more answers
It is known that the kinetics of recrystallization for some alloy obey the Avrami equation andthat the value of n in the exponen
Paul [167]

Answer:

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

Explanation:

For Avrami equation:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ k = \dfrac{-In(1-y)}{t^n}

To calculate the value of k which is a dependent variable for the above equation ; we have:

k = \dfrac{-In(1-0.40)}{200^{2.5}}

k = 9.030 \times 10 ^{-7}

The time needed for 50% transformation can be determined as follows:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ t =[ \dfrac{-In(1-y)}{k}]^{^{1/n}}

t_{0.5} =[ \dfrac{-In(1-0.4)}{9.030 \times 10^{-7}}]^{^{1/2.5}}

= 200.00183 min

The rate of reaction for Avrami equation is:

rate = \dfrac{1}{t_{0.5}}

rate = \dfrac{1}{200.00183}

rate = 0.00499 / min

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

8 0
3 years ago
Other questions:
  • What is the answer??
    8·2 answers
  • Volume measurements will be made using a 25-ml graduated cylinder, which has major scale divisions marked every 2 ml and minor s
    6·2 answers
  • Identify the type of reaction represented by each equation.
    12·2 answers
  • What is the volume of 0.200 mol of an ideal gas at 200 kPa and 400 K? A. 0.83 L B. 3.33 L C. 5.60 L D. 20.8 L
    12·2 answers
  • using hookes law, F s p r i n g = k^x , find the force needed to stretch a spring 2 cm if it has an elastic constant of 3 N/cm
    9·2 answers
  • What are the exceptions to the periodic trends in ionization energy?
    8·1 answer
  • How are electrons similar and different to the planet Earth?
    5·1 answer
  • The attractive forces between sodium and chloride ions are called:
    14·1 answer
  • 10 ml of solution of acetic acid is added to 250 ml volumetric flask , the concentration of diluted vinegar is 0.01 M. What is t
    11·1 answer
  • How many moles of AgCl can form from 6.5 moles of Ag and abundant HCl in the equation: 2Ag + 2HCl -&gt; 2AgCl + H2
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!