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Stella [2.4K]
3 years ago
11

X^2 = 25 ------ 289 (Solve for x)

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0
4114.5 Balance method used
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Please help!!!
noname [10]

Answer:

Just be yourself. Also, in most cases, it's helpful to just let the boy come to you. If he comes to you and says he likes you, you should also express your own feelings. ALWAYS be yourself. If you aren't yourself, the relationship will not work out. The boy should like you for who you are, not who you're trying or pretending to be.

4 0
3 years ago
Read 2 more answers
X-y=5 and x^2y=5x+6​
sergeinik [125]

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

To learn more on nonlinear equations: brainly.com/question/20242917

#SPJ1

8 0
1 year ago
Consider the table of the powers of 8.
garri49 [273]
C loser that’s the correct number
8 0
2 years ago
I find the value of X and the measurement of DAB
Leona [35]

Answer: What is the measure of ∠ DAB?

And we get that the measure of angle is 32 degrees.

Step-by-step explanation:

8 0
2 years ago
How do you solve <br> 69-3a=0
aleksandrvk [35]
69 - 3a = 0

69 - 3a (-69) = 0 (-69)

-3a = -69

-3a(/-3) = -69(/-3)

a = 23

hope this helps
8 0
3 years ago
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