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maria [59]
3 years ago
11

Please help! I’ll give brainliest if more than one person answers.

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

A. 384 in^2

B. Yes

Step-by-step explanation:

Part A.

What you do is use the formula for Surface Area of a rectangle which is 2lw+2wh+2lh. 2x9x12+2x12x4+2x9x4=384 in^2 is your answer.

Part B.

What you do is change the 3 ft ans 2 ft to inches which is 36 in and 24 in. You will then times those together to get 864. Yes, you will have enough gift wrap.

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Helpppp please ?????
BlackZzzverrR [31]
A) <DAE = 180-126 = 54
b) <EBC = 90 - 48 = 42
c) <BAE = 180-48-54=78
8 0
3 years ago
ANSWER PLEASE Tyler deposits $2000 and has a 8% interest compound quarterly. How much does he have Quarter 1,2,3,4 Show Work
guajiro [1.7K]

Answer:

If the time passed is only 3 months, then it is $2040

Step-by-step explanation:

We can use the quarterly compounded interest equation for this problem: P(1 + r/n)^nt

Step 1: Find out how much 3 months is in a year

<em>In this case, 3/12 which is 1/4</em>

Step 2: Plug in known variables into equation

2000[1 + (0.08)/4)]^[(4)(1/4)]

Step 3: Solve/Plug in calc

You will get $2040

If the time passed in the problem is 1 year, then we can be able to solve how much money he earned per quarter. However, since only 3 months have elapsed, then he has only earned $2040.

7 0
3 years ago
Evans dog weighs 63 pounds. Oxanas dog weighs 9 pounds. How much more does evan’s dog weigh than oxanas dog?
natima [27]

Answer:54pounds

Step-by-step explanation:63-9=54

7 0
3 years ago
Read 2 more answers
Evaluate q2+p; use p=5, and q=2 ​
mars1129 [50]

Answer:

9

Step-by-step explanation:

(2)2 + 5 = 4 + 5 = 9

8 0
3 years ago
Read 2 more answers
Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

                 =\frac{2ab^2\cdot \:5-a^2b^2}{5}

                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

7 0
3 years ago
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