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4 years ago

11

One joule of work is needed to move one coulomb of charge from one point to another with no change in velocity. Which of the fol

lowing is true between the two points?
a.) The resistance is one ohm.
b.) The current is one ampere.
c.) The potential difference is one volt.
d.) The electric field strength is one newton per coulomb.
e.) The electric field strength is one joule per electron.

1 answer:

podryga [215]4 years ago

6 0

It B the current is one ampere

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Consider a metal single crystal oriented such that the normal to the slip plane and slip direction are at angles of 60° and 35°,

Vedmedyk [2.9K]

Answer:

19.5324 MPa

Explanation:

Information provided

Angle between the normal to the slip plane with tensile axis, $\alpha=60^{o}
$

Angle by slip direction with tensile axis, $\beta=35^{o}$

Critical resolved shear stress, $\tau_{c}=8 MPa$

Applied stress $\sigma=12 MPa$

Shear stress at slip plane

$\tau=\sigma cos\alpha cos\beta$

$\tau=12cos60^{o}cos35^{o}=4.915 MPa$

$\tau$ hence crystal won’t yield

Applied stress, $\sigma$ for crystal to yield is given by

$\sigma=\frac {\tau_{c}}{cos\alpha cos\beta}$

$\sigma=\frac {8}{cos60cos35}=19.53239342 MPa$

$\sigma=19.5324 MPa
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3 years ago

Pulsars are neutron stars that emit X rays and other radiation in such a way that we on Earth receive pulses of radiation from t

stira [4]

Answer:

(a) $a_{c} = 5.41\times 10^{9} m/s^{2}$

(b) $a_{t} = 2.99\times 10^{- 5} m/s^{2}$

Given:

Time period of Pulsar, $T_{P} = 33.085 ms == 33.085\times 10^{- 3} s$

Equatorial radius, R = 15 Km = 15000 m

Spinning time, $t_{s} = 9.50\times 10^{10}$

Solution:

(a) To calculate the value of the centripetal acceleration, $a_{c}$ on the surface of the equator, the force acting is given by the centripetal force:

$m\times a_{c} = \frac{mv_{c}^{2}}{R}$

$a_{c} = \frac{v_{c}^{2}}{R}$ (1)

where

$v_{c} = \frac{distance covered(i.e., circumference)}{ T}$

$v_{c} = \frac{2\pi R}{Time period, T}$ (2)

Now, from (1) and (2):

$a_{c} = R\frac({2\pi )^{2}}{T^{2}}$

$a_{c} = 15000\frac{2\pi )^{2}}{(33.085\times 10^{- 3})^{2}}$

$a_{c} = 5.41\times 10^{9} m/s^{2}$

(b) To calculate the tangential acceleration of the object :

The tangential acceleration of the object will remain constant and is given by the equation of motion as:

$v = u + a_{t}t_{s} = 0$

where

u = $v_{c}$

$a_{t} = - \frac{2\pi R}{Tt_{s}}$

$a_{t} = - \frac{2\pi 15000}{33.085\times 10^{- 3}\times 9.50\times 10^{10}}$

$a_{t} = 2.99\times 10^{- 5} m/s^{2}$

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3 years ago

Which statement best describes the work and energy in these examples?

solniwko [45]

Answer: <u>Option A: </u>The gas and food are examples of energy.

Explanation:

Work and energy are inter-related. Energy is required to do the work. An equal amount of energy is converted into work. Work and energy have same units. The SI unit is Joule.

The gas and food are sources of energy. They act as fuel. This energy is utilized to perform work. The gas is used to run the car. The food is metabolized inside the body which is a source of energy and utilized to perform every day work.

Hence, The gas and food are examples of energy.

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Some1 pushes u and then u defend your self

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3 years ago

There have been different models of the atom over time. How has the competition between these models affected our understanding

Umnica [9.8K]

Each time it gets changed we understand more about it

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