Answer:
just wait I'll subscribe yours
<h2>hope it helps you have a good day keep smiling be happy stay safe</h2>
Answer:
733.9× 2.4
1761.36
Explanation:
The airplane refuels between city A and continues on to city B. It travels at an average speed of 733.9km/h. If the trip takes 2.4 hours, what is the flight distance between city A and city B?
The speed of the combined carts after the collision is 0.25 m/s
Explanation:
We can solve this problem by using the principle of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:
where:
is the mass of the first cart
is the initial velocity of the first cart
is the mass of the second cart
is the initial velocity of the second cart
is the final combined velocity of the two carts
Re-arranging the equation and substituting the values, we find: the final velocity:
Learn more about momentum:
brainly.com/question/7973509
brainly.com/question/6573742
brainly.com/question/2370982
brainly.com/question/9484203
#LearnwithBrainly
Answer:
5000 Pa
Explanation:
First collect the data you've been given already and make sure to convert into the right units;
<em>Density</em><em> </em><em>=</em><em> </em><em>1</em><em> </em><em>g</em><em>/</em><em>cm³</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>Kg</em><em>/</em><em> </em><em>m³</em>
<em>acceleration</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>gravity</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>m</em><em>/</em><em>s²</em>
<em>Height</em><em> </em><em>=</em><em> </em><em>5</em><em>0</em><em> </em><em>cm</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>0</em><em>.</em><em>5</em><em> </em><em>m</em>
after collecting the data, use the formula to solve
<em>pressure</em><em> </em><em>=</em><em> </em><em>pgh</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>0</em><em>0</em><em> </em><em>×</em><em> </em><em>1</em><em>0</em><em> </em><em>×</em><em> </em><em>0</em><em>.</em><em>5</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>5</em><em>0</em><em>0</em><em>0</em><em> </em><em>Pa</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>
The position is a cosine function, so the particle is at the origin
whenever the cosine is zero.
The first point where the cosine is zero occurs when the angle is π/2 .
That happens when √t = π/2 , so t = π² / 4 is the point where we need
the particle's speed.
Speed is the first derivative of the position.
The derivative with respect to 't' of cos(√t) is [ -1 / (2√t) sin(√t) ] . (chain derivative.)
The speed when [ t = π² / 4 ] is . . .
-1 / 2√(π² / 4) times sin(√(π² / 4)) = -(1 / π) times sin(π/2) = -(1/π) times (1) = -(1/π) .
The first time when the particle is at the origin, it's moving backwards,
into [ -x ] territory, and its speed is (1/π) = about 0.3183... . (rounded)
There you have its speed and direction, so you have its velocity.