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aev [14]
3 years ago
6

There have been different models of the atom over time. How has the competition between these models affected our understanding

of the atom?
Physics
2 answers:
Reil [10]3 years ago
7 0

Answer:

Generally, these models have shed more light on the field of atom by describing the composition of atoms and how the atom functions . The competition of these models have been able to modify atomic model to it actual description, modification and functionality.      

Explanation:

There have been different models of atoms overtime . The competition between the various models of atom have been able to shed more light on atom and create more theory on the subject of atoms. The well known models of atom are Dalton's atomic model, Thomson's model of the atom , Ernest Rutherford model of atom, Niels Bohr's model and Schrödinger's model of atoms.

Dalton stated that atoms are indivisible and he was able to realize atom of a particular element different from others . That means atoms of the same element are identical. J.J Thompson was able to recognized electrons in atoms  he drew a plum pudding model  of an atom. It shows electron revolves around a positive charge through out a spherical cloud. Rutherford was able to detect positive charge of an atom found in the nucleus of an atom. Bohr's model modified Rutherford's model . He was able to recognized that the electron move or orbit around the nucleus. Schrödinger's  believes electrons moves around the nucleus in cloud and has an uncertain position.

Generally, these models have shed more light on the field of atom by describing the composition of atoms and how the atom functions . The competition of these models have been able to modify atomic model to it actual description, modification and functionality.      

Umnica [9.8K]3 years ago
4 0
Each time it gets changed we understand more about it
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On a 100km track , a train travels the first 30km with a speed of 30km/h . How fast the train travel the next 70 km if the avera
nirvana33 [79]

Solution :-

Given :

Distance 1 = 30 km

Distance 2 = 70 km

We know that speed = distance/time

and, Average speed = total distance/total time taken

When the train acquired a speed of 30 km/hr, the time taken = 30/30 = 1 hour

Average speed = 9distance 1 + distance 2)/(time 1 + time 2)

AS time 2 or t2 is time taken for the second part of the journey of 70 km

⇒ 40 = 100/(1 + t2)

⇒ 40 + 40t2 = 100

⇒ 40t2 = 100 - 40

⇒ 40t2 = 60

⇒ t2 = 60/40

⇒ t2 = 1.5

So, t2 or time taken to travel the second part of the journey is 1.5 hours.

Speed of the second part of the journey = distance 2/time 2

⇒ 70/1.5

⇒ 46.666 km/hr or 46.7 km/hr.

Hence the answer is = 46.666 km/hr or 46.7 km/hr.

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

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3 0
4 years ago
In this experiment we will observe the magnetic fields produced by a current carrying wire. A long wire is suspended vertically,
Alisiya [41]

Answer:

See explanation

Explanation:

Solution:-

Electric current produces a magnetic field. This magnetic field can be visualized as a pattern of circular field lines surrounding a wire. One way to explore the direction of a magnetic field is with a compass, as shown by a long straight current-carrying wire in. Hall probes can determine the magnitude of the field. Another version of the right hand rule emerges from this exploration and is valid for any current segment—point the thumb in the direction of the current, and the fingers curl in the direction of the magnetic field loops created by it.

Compasses placed near a long straight current-carrying wire indicate that field lines form circular loops centered on the wire. Right hand rule 2 states that, if the right hand thumb points in the direction of the current, the fingers curl in the direction of the field. This rule is consistent with the field mapped for the long straight wire and is valid for any current segment.

( See attachments )

- The equation for the magnetic field strength - B - (magnitude) produced by a long straight current-carrying wire is given by the Biot Savart Law:

                                  B = \frac{uo*I}{2\pi *r}

Where,

I : The current,

r : The shortest distance to the wire,

uo : The permeability of free space. = 4π * 10^-7  T. m/A

-  Since the wire is very long, the magnitude of the field depends only on distance from the wire r, not on position along the wire. This is one of the simplest cases to calculate the magnetic field strength - B - from a current.

- The magnetic field of a long straight wire has more implications than one might first suspect. Each segment of current produces a magnetic field like that of a long straight wire, and the total field of any shape current is the vector sum of the fields due to each segment. The formal statement of the direction and magnitude of the field due to each segment is called the Biot-Savart law. Integral calculus is needed to sum the field for an arbitrary shape current. The Biot-Savart law is written in its complete form as:

                             B = \frac{uo*I}{4\pi }*\int\frac{dl xr}{r^2}      

Where the integral sums over,

 1) The wire length where vector dl = direction of current (in or out of plane)

 2) r is the distance between the location of dl and the location at which the magnetic field is being calculated

 3)  r^ is a unit vector in the direction of r.

   

3 0
3 years ago
jack and his family go to the movies first they eat lunch at 1:30 pm it takes 40 minutes to eat then the movie then they drive 2
BabaBlast [244]
The answer would be 2:25
8 0
3 years ago
Read 2 more answers
Consider the addition of an electron to the following atoms from the third period. Rank the atoms in order from the most negativ
sergeinik [125]

The question is incomplete, the atoms in the third period referred to in the question are shown in the image attached.

Answer:

Cl>Si>Ar

Explanation:

Electron affinity refers to the energy released when an atom accepts electron (s) to form a negative ion. It is a periodic property that shows similar trends as electro negativity.

Considering the atoms in period three given in the question; chlorine will have the most negative value of electron affinity. This owes to the fact that halogens accept electrons easily to form negative ions. Silicon in group 14 shows much less negative value of electron affinity while argon, a noble gas, does not accept electrons at all and has an electron affinity of zero KJMol-1 by standard.

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4 years ago
A girl walks 2 meters north 4 meters west and 2 meters south her final displacement is:
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