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aev [14]
3 years ago
6

There have been different models of the atom over time. How has the competition between these models affected our understanding

of the atom?
Physics
2 answers:
Reil [10]3 years ago
7 0

Answer:

Generally, these models have shed more light on the field of atom by describing the composition of atoms and how the atom functions . The competition of these models have been able to modify atomic model to it actual description, modification and functionality.      

Explanation:

There have been different models of atoms overtime . The competition between the various models of atom have been able to shed more light on atom and create more theory on the subject of atoms. The well known models of atom are Dalton's atomic model, Thomson's model of the atom , Ernest Rutherford model of atom, Niels Bohr's model and Schrödinger's model of atoms.

Dalton stated that atoms are indivisible and he was able to realize atom of a particular element different from others . That means atoms of the same element are identical. J.J Thompson was able to recognized electrons in atoms  he drew a plum pudding model  of an atom. It shows electron revolves around a positive charge through out a spherical cloud. Rutherford was able to detect positive charge of an atom found in the nucleus of an atom. Bohr's model modified Rutherford's model . He was able to recognized that the electron move or orbit around the nucleus. Schrödinger's  believes electrons moves around the nucleus in cloud and has an uncertain position.

Generally, these models have shed more light on the field of atom by describing the composition of atoms and how the atom functions . The competition of these models have been able to modify atomic model to it actual description, modification and functionality.      

Umnica [9.8K]3 years ago
4 0
Each time it gets changed we understand more about it
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A cannonball is fired perfectly horizontally from the top of a 210 m tall cliff. It is fired with an initial velocity of 50 m/s.
pochemuha

Answer:

the horizontal distance covered by the cannonball before it hits the ground is 327.5 m

Explanation:

Given;

height of the cliff, h = 210 m

initial horizontal velocity of the cannonball, Ux = 50 m/s

initial vertical velocity of the cannonball, Uy = 0

The time for the cannonball to reach the ground is calculated as;

h = u_yt - \frac{1}{2} gt^2\\\\h = 0 - \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 210}{9.8} }\\\\t  = 6.55 \ s

The horizontal distance covered by the cannonball before it hits the ground is calculated as;

X = U_x \times \ t\\\\X = 50 \times \ 6.55\\\\X = 327.5 \ m

Therefore, the horizontal distance covered by the cannonball before it hits the ground is 327.5 m

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