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Tems11 [23]
3 years ago
14

What’s the best answer

Chemistry
1 answer:
In-s [12.5K]3 years ago
7 0
C) is correct, because there are 2 carbons and 4 oxygens on both sides, making the equation balanced.
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Question 2 Calculate the pH of a solution that has an acetic acid concentration of 0.05 M and a sodium acetate concentration of
Eva8 [605]

Answer : The pH of the solution is, 4.9

Explanation : Given,

Dissociation constant for acetic acid = K_a=1.8\times 10^{-5}

Concentration of acetic acid = 0.05 M

Concentration of sodium acetate = 0.075 M

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.8\times 10^{-5})

pK_a=5-\log (1.8)

pK_a=4.7

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[CH_3COONa]}{[CH_3COOH]}

Now put all the given values in this expression, we get:

pH=4.7+\log (\frac{0.075}{0.05})

pH=4.9

Therefore, the pH of the solution is 4.9.

8 0
3 years ago
Which of the following is a product formed when Ag2O decomposes?
ASHA 777 [7]

The product formed when Ag2O decompose is O2 ( answer c)

explanation

Decomposition involve separation of a single chemical compound into two ore more elemental parts Ag2O decomposes to yield Ag and O2

that is 2Ag2O→ 4Ag + O2

2 moles of Ag2O decomposes to yield 4 moles of Ag and 1 mole of O2

6 0
3 years ago
Read 2 more answers
A titanium cube contains 3.10•10^23 atoms. The density of a titanium is 4.50g/cm^3. What is the edge length of the cube?
Lerok [7]

Answer:

1.76cm

Explanation:

We'll begin by calculating the mass of titanium that contain 3.10x10²³ atoms. This can be obtained as follow:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10²³ atoms. This implies that 1 mole of titanium also contains 6.02x10²³ atoms.

1 mole of titanium = 48g

Now, if 48g of titanium contains 6.02x10²³ atoms,

Then Xg of titanium will contain 3.10x10²³ atoms i.e

Xg of titanium = (48x3.10x10²³)/6.02x10²³

Xg of titanium = 24.72g

Next, we shall determine the volume of the titanium. This is illustrated below:

Density of titanium = 4.50g/cm³

Mass of titanium = 24.72g

Volume of titanium =..?

Density = Mass /volume

Volume = Mass /Density

Volume of titanium = 24.72g/4.50g/cm³

Volume of titanium = 5.49cm³

Finally we shall determine the edge length of the titanium cube as follow:

Volume = L³

5.49cm³ = L³

Take the cube root of both side

L = 3√(5.49cm³)

L = 1.76cm

Therefore, the edge length is 1.76cm

5 0
3 years ago
How many neutrons are there in 9 molecules of P4 with mass number 31 and proton number 15?
aalyn [17]

A = mass number which is equal to the total number of protons + number of neutrons, Z= atomic number of any element which is also indicates Number of protons or number of electron in the given atom.


The formula to calculate neutron would be :

mass number - proton  

31   - 15     = 16

Thus 16 neutrons are found in one atom of P  

There are 4 atom in one molecule

Thus  

4 atom /1 molecule * 9 molecule * 16 neutron / 1 atom  

= 4*9*16= 576 neutrons


7 0
3 years ago
Read 2 more answers
Calculate the solubility of ( = ) in moles per liter. Ignore any acid–base properties. s = mol/L Calculate the solubility of ( =
BaLLatris [955]

This is an incomplete question, here is a complete question.

Calculate the solubility of each of the following compounds in moles per liter. Ignore any acid-base properties.

CaCO₃, Ksp = 8.7 × 10⁻⁹

Answer : The solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

Explanation :

As we know that CaCO₃ dissociates to give Ca^{2+} ion and CO_3^{2-} ion.

The solubility equilibrium reaction will be:

CaCO_3\rightleftharpoons Ca^{2+}+CO_3^{2-}

The expression for solubility constant for this reaction will be,

K_{sp}=[Ca^{2+}][CO_3^{2-}]

Let solubility of CaCO₃ be, 's'

K_{sp}=(s)\times (s)

K_{sp}=s^2

8.7\times 10^{-9}=s^2

s=9.33\times 10^{-5}mol/L

Therefore, the solubility of CaCO₃ is, 9.33\times 10^{-5}mol/L

4 0
3 years ago
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