9.0532e-5 should be correct! hope this helps
Answer:
What is the formula for elevation in boiling point?
Explanation:
The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation. Where, i is the Van't Hoff factor.
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Boiling Point Elevation Formula.
Solvent Kb value (in oC.kg.mol-1)
Chloroform 3.63
Benzene 2.53
By use of ideal gas equation PV= nRT where n is the number of moles,P = pressure, V = volume, R= gas constant (0.08206 L. atm/ mol.k) ant T is the temperature,
to calculate the number of moles(n) =PV/RT
convert ml to L, that is 200/1000= 0.2 L
convert mmHg to atm, that is 780mm hg x 1atm/ 760 mm hg= 1.026 atm
convert temperature to kelvin, that is 135 +273= 408 k
n is therefore= (0.2 x 1.026)/ ( 0.08206 x 408)= 6.129 x10^-3 moles
from avogadro constant 1moles = 6.02 x10^23 molecules what about 6 .129 x10^-3 moles
= ( 6.02 x10^23) x (6.129 x10^-3)/ 1mole = 3.69 x10^21 molecules
Answer:
The figures and parameters to answer this question are not clearly stated, so I will answer it in the closest best way I can.
Explanation:
Molality of alanine = mole / weight of solvent( kg)
= (170×1000)/(89×600)
= 3.18 molal
We know ∆ Tf = Kf × m
Kf = ∆ Tf / molality
= 7.9/3.18 = 2.48 °c.kg.mol-1
Now using the value of cryoscopic constant we calculate can't Hoff factor for Ammonium chloride.
i = ∆ Tf /( Kf × molality of NH4Cl)
= (24.7 × 53.5 × 600) /(2.48 × 170 × 1000)
= 1.8
