Answer:
the first one is energy level
Explanation:
PE = mgh
where
m = mass
g = acceleration due to gravity
h = height
Answer:
Speed at which the ball passes the window’s top = 10.89 m/s
Explanation:
Height of window = 3.3 m
Time took to cover window = 0.27 s
Initial velocity, u = 0m/s
We have equation of motion s = ut + 0.5at²
For the top of window (position A)
![s_A=0\times t_A+0.5\times 9.81t_A^2\\\\s_A=4.905t_A^2](https://tex.z-dn.net/?f=s_A%3D0%5Ctimes%20t_A%2B0.5%5Ctimes%209.81t_A%5E2%5C%5C%5C%5Cs_A%3D4.905t_A%5E2)
For the bottom of window (position B)
![s_B=0\times t_B+0.5\times 9.81t_B^2\\\\s_A=4.905t_B^2](https://tex.z-dn.net/?f=s_B%3D0%5Ctimes%20t_B%2B0.5%5Ctimes%209.81t_B%5E2%5C%5C%5C%5Cs_A%3D4.905t_B%5E2)
![\texttt{Height of window=}s_B-s_A=3.3\\\\4.905t_B^2-4.905t_A^2=3.3\\\\t_B^2-t_A^2=0.673](https://tex.z-dn.net/?f=%5Ctexttt%7BHeight%20of%20window%3D%7Ds_B-s_A%3D3.3%5C%5C%5C%5C4.905t_B%5E2-4.905t_A%5E2%3D3.3%5C%5C%5C%5Ct_B%5E2-t_A%5E2%3D0.673)
We also have
![t_B-t_A=0.27](https://tex.z-dn.net/?f=t_B-t_A%3D0.27)
Solving
![t_B=0.27+t_A\\\\(0.27+t_A)^2-t_A^2=0.673\\\\t_A^2+0.54t_A+0.0729-t_A^2=0.673\\\\t_A=1.11s\\\\t_B=0.27+1.11=1.38s](https://tex.z-dn.net/?f=t_B%3D0.27%2Bt_A%5C%5C%5C%5C%280.27%2Bt_A%29%5E2-t_A%5E2%3D0.673%5C%5C%5C%5Ct_A%5E2%2B0.54t_A%2B0.0729-t_A%5E2%3D0.673%5C%5C%5C%5Ct_A%3D1.11s%5C%5C%5C%5Ct_B%3D0.27%2B1.11%3D1.38s)
So after 1.11 seconds ball reaches at top of window,
We have equation of motion v = u + at
![v_A=0+9.81\times 1.11=10.89m/s](https://tex.z-dn.net/?f=v_A%3D0%2B9.81%5Ctimes%201.11%3D10.89m%2Fs)
Speed at which the ball passes the window’s top = 10.89 m/s
Weow that’s cool but what is your question
B because the mantle is farther down in and a egg has more of the hard stuff inside