Answer:
9.801 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity = 39 ft/s
s = Displacement = 720 cm = 7.2 m
a = Acceleration
Converting to m/s

Equation of motion

Acceleration of the ball is 9.801 m/s²
Answer:
D. Upward and to the left

Actually Welcome to the Concept of the Force.
Force = Mass * Acceleration.
here, Mass = 45 kg and Force = 65 N
hence, Acceleration = 65/45
===> Acc. = 1.44 m/s^2
hence the acceleration is 1.44 m/s^2
ok
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Answer
given,
initial velocity of skateboard = 5.1 m/s
angle above the horizontal = 55°
height of the ramp = 1 m
a) maximum height of projectile


H = 0.889 m
the maximum height of the skateboard above the ground
= 1 + 0.889
= 1.889 m
b) time to reach the height
t = 0.426 s
horizontal distance = u cos θ × t
= 5.1 × cos 55° × 0.426
horizontal distance = 1.25 m